我有一个数据框x:
dput(x)
structure(list(District = structure(c(6L, 6L, 6L, 6L, 6L, 6L), .Label = c("District - Central (06)",
"District - East (04)", "District - New Delhi (05)", "District - North (02)",
"District - North East (03)", "District - North West (01)", "District - South (09)",
"District - South West (08)", "District - West (07)"), class = "factor"),
Age = structure(c(103L, 1L, 2L, 14L, 25L, 36L), .Label = c("0",
"1", "10", "100+", "11", "12", "13", "14", "15", "16", "17",
"18", "19", "2", "20", "21", "22", "23", "24", "25", "26",
"27", "28", "29", "3", "30", "31", "32", "33", "34", "35",
"36", "37", "38", "39", "4", "40", "41", "42", "43", "44",
"45", "46", "47", "48", "49", "5", "50", "51", "52", "53",
"54", "55", "56", "57", "58", "59", "6", "60", "61", "62",
"63", "64", "65", "66", "67", "68", "69", "7", "70", "71",
"72", "73", "74", "75", "76", "77", "78", "79", "8", "80",
"81", "82", "83", "84", "85", "86", "87", "88", "89", "9",
"90", "91", "92", "93", "94", "95", "96", "97", "98", "99",
"Age not stated", "All ages"), class = "factor"), Total = c(3656539L,
56131L, 58644L, 63835L, 63859L, 64945L), Rural = c(213950L,
3589L, 3757L, 4200L, 4102L, 4223L), Urban = c(3442589L, 52542L,
54887L, 59635L, 59757L, 60722L)), .Names = c("District",
"Age", "Total", "Rural", "Urban"), row.names = c(NA, 6L), class = "data.frame")
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我想拆分District列以将地区名称提取到新列中Name。例如,“区 - 西北 (01)”应拆分为“西北”。我尝试str_split_fixed并得到:
x
District Age Total Rural Urban 1 name
1 District - North West (01) All ages 3656539 213950 3442589 North West (01)
2 District - North West (01) 0 56131 3589 52542 North West (01)
3 District - North West (01) 1 58644 3757 54887 North West (01)
4 District - North West (01) 2 63835 4200 59635 North West (01)
5 District - North West (01) 3 63859 4102 59757 North West (01)
6 District - North West (01) 4 64945 4223 60722 North West (01)
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我尝试再次使用相同的函数来拆分name列以将地区名称与代码分开,但它给出了以下错误:
stri_split_regex 中的错误(字符串,模式,n = n,简化 = TRUE,opts_regex = attr(模式,:正则表达式模式中的嵌套括号不正确。(U_REGEX_MISMATCHED_PAREN)
有没有办法根据单个函数中的模式将字符列拆分为多个列?
你可以使用
library(stringr)
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data.frame(str_split_fixed(df$District, " ", 3))
X1 X2 X3
1 District - North West (01)
2 District - North West (01)
3 District - North West (01)
4 District - North West (01)
5 District - North West (01)
6 District - North West (01)
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您可以用来gsub删除此处多余的东西,
gsub("[[:digit:]]","",df$X3)
gsub("[[:punct:]]","",df$X3)
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ETC。