使用多种变体替换Foreach字符串

Sop*_*des 8 php arrays loops

我试图找出使用多个排序规则进行字符串替换的最佳方法.

我有一个由用户插入的句子,我有一个数组,其中包含该句中所有拼写错误的单词及其可能的更正.

$sentence = 'i want to recovary my vehical from the cabs';

我想显示以下内容:

  1. 我想从出租车上恢复我的车辆
  2. 我想从出租车里恢复我的车辆
  3. 我想从出租车上取回我的车辆

代码到目前为止:

$element = array(
    "vehical" => array('vehicle'),
    "recovary" => array('recovery', 'recover', 'revary')
);

$sentence = 'i want to recovary my vehical from the cabs';

foreach($element as $i => $val){
    echo $i;    
}
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编辑:扩展了另一种情况:

如果顶部数组中存在多个变体,会发生什么.

    "vehical" => array('vehicle', 'vehiclesy', 'whatever'),
    "recovary" => array('recovery', 'recover', 'revary')
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  1. 我想从出租车上恢复我的车辆
  2. 我想从出租车里恢复我的车辆
  3. 我想从出租车里恢复我的任何东西
  4. 我想从出租车里恢复我的车辆
  5. 我想从出租车里恢复我的车辆
  6. 我想从出租车里找回我的东西
  7. 我想从出租车上取回我的车辆
  8. 我想从出租车里复活我的车辆
  9. 我想从出租车里复活我的任何东西

Yos*_*shi 2

您需要创建替换数据的所有唯一组合。对于每个组合,您都可以进行替换。这是一种方法:

<?php
function createCombinations(array $input)
{
    $head = array_shift($input);
    $tail = count($input) > 1 ? createCombinations($input) : array_shift($input);

    $combinations = [];
    foreach ($head as $left) {
        foreach ($tail as $right) {
            $combinations[] = array_merge([$left], (array) $right);
        }
    }

    return $combinations;
}

$element = [
    'vehical'  => ['vehicle', 'car'],
    'recovary' => ['recovery', 'recover', 'revary'],
    'cubs'     => ['cabs'],
];

$sentence = 'i want to recovary my vehical from the cubs';
$from = array_keys($element);

foreach (createCombinations($element) as $to) {
    echo str_replace($from, $to, $sentence), "\n";
}

# => i want to recovery my vehicle from the cabs
# => i want to recover my vehicle from the cabs
# => i want to revary my vehicle from the cabs
# => i want to recovery my car from the cabs
# => i want to recover my car from the cabs
# => i want to revary my car from the cabs
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演示: https: //ideone.com/LERb9X