比Stackwalk更快

Question

有没有人知道更好/更快的方式获得调用堆栈比"StackWalk"？我也认为对于有很多变量的方法,stackwalk也可能会变慢...(我想知道商业分析器的用途是什么？)我在Windows上使用C++.:) 谢谢 :)

Answer 1

我不知道它是否更快，并且它不会向您显示任何符号，而且我确信您可以做得更好，但这是我不久前需要此信息时编写的一些代码（仅适用于视窗）：

struct CallStackItem
{
    void* pc;
    CallStackItem* next;

    CallStackItem()
    {
        pc = NULL;
        next = NULL;
    }
};

typedef void* CallStackHandle;

CallStackHandle CreateCurrentCallStack(int nLevels)
{
    void** ppCurrent = NULL;

    // Get the current saved stack pointer (saved by the compiler on the function prefix).
    __asm { mov ppCurrent, ebp };

    // Don't limit if nLevels is not positive
    if (nLevels <= 0)
        nLevels = 1000000;

    // ebp points to the old call stack, where the first two items look like this:
    // ebp -> [0] Previous ebp
    //        [1] previous program counter
    CallStackItem* pResult = new CallStackItem;
    CallStackItem* pCurItem = pResult;
    int nCurLevel = 0;

    // We need to read two pointers from the stack
    int nRequiredMemorySize = sizeof(void*) * 2;
    while (nCurLevel < nLevels && ppCurrent && !IsBadReadPtr(ppCurrent, nRequiredMemorySize))
    {
        // Keep the previous program counter (where the function will return to)
        pCurItem->pc = ppCurrent[1];
        pCurItem->next = new CallStackItem;

        // Go the the previously kept ebp
        ppCurrent = (void**)*ppCurrent;
        pCurItem = pCurItem->next;
        ++nCurLevel;
    }

    return pResult;
}

void PrintCallStack(CallStackHandle hCallStack)
{
    CallStackItem* pCurItem = (CallStackItem*)hCallStack;
    printf("----- Call stack start -----\n");
    while (pCurItem)
    {
        printf("0x%08x\n", pCurItem->pc);
        pCurItem = pCurItem->next;
    }
    printf("-----  Call stack end  -----\n");
}

void ReleaseCallStack(CallStackHandle hCallStack)
{
    CallStackItem* pCurItem = (CallStackItem*)hCallStack;
    CallStackItem* pPrevItem;
    while (pCurItem)
    {
        pPrevItem = pCurItem;
        pCurItem = pCurItem->next;
        delete pPrevItem;
    }
}