Mar*_*ior 10 java gis geospatial geotools
首先,我是GIS的新手,所以请原谅任何错误.我需要发现纬度和经度点与纬度/经度多边形(常规或非常规)之间的距离.确切地说,我需要发现从给定点到多边形边界中的点的最小距离,如下所示.在该示例中,从点p
到多边形的距离越近d
.注意:我不需要点,只需要最小距离.
经过一些阅读,我使用GeoTools API提出了以下最低工作示例.但是,我认为我搞砸了输出.谁能让我知道如何在mteres中获得点和多边形之间的最小距离?
MWE.java:
import com.vividsolutions.jts.geom.Coordinate;
import com.vividsolutions.jts.geom.Geometry;
import com.vividsolutions.jts.geom.GeometryFactory;
import com.vividsolutions.jts.geom.Point;
public class MWE {
public static void main(String[] args) throws Exception {
GeometryFactory gf = JTSFactoryFinder.getGeometryFactory();
Coordinate[] c = new Coordinate[5];
c[0] = new Coordinate(-49.242986, -16.662430);
c[1] = new Coordinate(-49.241999, -16.664465);
c[2] = new Coordinate(-49.239146, -16.663828);
c[3] = new Coordinate(-49.239832, -16.661443);
c[4] = new Coordinate(-49.242986, -16.662430);
Geometry geo = gf.createPolygon(c);
Point p = gf.createPoint(new Coordinate(-49.246870, -16.665493));
double distance = geo.distance(p);
System.out.println("Distance: " + distance);
}
}
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小智 7
所以你正在做的是正确的,但它将返回大地测量单位(弧度)而不是米的距离.您有两种选择:
要使用GeodeticCalculator,您需要确定多边形边界上与点的最近点.例如DistanceOp.closestPoints(geo, p)[0]
// adapted from http://docs.geotools.org/stable/userguide/library/referencing/calculator.html
CoordinateReferenceSystem crs = CRS.decode("EPSG:4326");
GeodeticCalculator gc = new GeodeticCalculator(crs);
gc.setStartingPosition( JTS.toDirectPosition( DistanceOp.closestPoints(geo, p)[0], crs ) );
gc.setDestinationPosition( JTS.toDirectPosition( p, crs ) );
double distance = gc.getOrthodromicDistance();
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