LSApplicationQueriesSchemes和派生数据

Question

我想在我的应用程序中打开一个whatsapp url.

let whatsAppUrl = NSURL(string: "whatsapp://send?text=Hello%2C%20World!")
if UIApplication.sharedApplication().canOpenURL(whatsAppUrl!) {
    UIApplication.sharedApplication().openURL(whatsAppUrl!)
}

我使用字典"LSApplicationQueriesSchemes"扩展我的info.plist并为whatsapp添加我的url方案.

<key>LSApplicationQueriesSchemes</key>
<dict>
    <key>Item 0</key>
    <string>whatsapp</string>
</dict>

如果我运行我的应用程序,我收到以下错误消息.

"This app is not allowed to query for scheme whatsapp"

我阅读了一些清理派生数据的解决方案并再次运行应用程序以解决此问题.但这对我没有帮助,对我的问题存在另一种解决方案吗？

Answer 1

您已经将LSApplicationQueriesSchemes设为a dict,它必须是一个数组,就像这样,然后它将工作:).

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>whatsapp</string>
</array>

我还建议你不要打开可选的URL !,你可以这样做:

guard 
   let whatsAppUrl = URL(string: "whatsapp://send?text=Hello%2C%20World!"),
   case let application = UIApplication.shared,
    application.canOpenURL(whatsAppUrl) 
else { return }
application.openURL(whatsAppUrl)

Answer 2

let url = "whatsapp://send?text=Hello World!"
 if let urlString = url.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet()) {
  if let whatsappURL = NSURL(string: urlString) {
   if UIApplication.sharedApplication().canOpenURL(whatsappURL) {
       UIApplication.sharedApplication().openURL(whatsappURL)
        } 
       }}

并定义这样的查询方案

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>whatsapp</string>
</array>