PHP是否具有结构或枚举,如果不是,它们的最佳实现是什么？

Question

NOTICE!: This question is not a duplicate: I have provided below an alternative and highly useful enumeration method that accomplishes the desired effect - 11/13/2013

typedefPHP中是否有关键字,以便我可以执行以下操作:

typedef struct {

} aStructure;

要么

typedef enum {
  aType1,
  aType2,
} aType;

编辑

我最终在下面回答了我自己的问题(跳过第一个最近的回答).我创建了一个自定义enum函数,完全满足我的要求,但没有类型定义.

Answer 1

我实际上为PHP创建了自己的枚举,它可以很好地满足我的需要.没有typedef但它很好:D

函数枚举($ array,$ asBitwise = false)

    /*
     * I formed another version that includes typedefs
     * but seeing how this hacky is not viewed as compliant
     * with programming standards I won't post it unless someone
     * wishes to request. I use this a lot to save me the hassle of manually
     * defining bitwise constants, but if you feel it is too pointless
     * for you I can understand. Not trying to reinvent the wheel here
     *
     */
    function enum(array $array, bool $asBitwise = false) {

        if(!is_array($array) || count($array) < 1)  return false;    // Error incorrect type

        $n = 0; // Counter variable
        foreach($array as $i) {
            if(!define($i, $n == 0 ? 0 : ($asBitwise ? 1 << ($n - 1) : $n))) return false;
            ++$n;
        } 
        return true; // Successfully defined all variables

    }

用法(示例):

    enum([
        'BrowserTypeUnknown',       // 0
        'BrowserTypeIE',            // 1
        'BrowserTypeNetscape',      // 2
        'BrowserTypeOpera',         // 3
        'BrowserTypeSafari',        // 4
        'BrowserTypeFirefox',       // 5
        'BrowserTypeChrome',        // 6
    ]); // BrowserType as an Increment

    $browser_type = BrowserTypeChrome;

    if($browser_type == BrowserTypeOpera) {
        // Make Opera Adjustments (will not execute)
    } else
    if($browser_type == BrowserTypeChrome) {
        // Make Chrome Adjustments (will execute)
    }

    enum([
        'SearchTypeUnknown',            // 0
        'SearchTypeMostRecent',         // 1 << 0
        'SearchTypePastWeek',           // 1 << 1
        'SearchTypePastMonth',          // 1 << 2
        'SearchTypeUnanswered',         // 1 << 3
        'SearchTypeMostViews',          // 1 << 4
        'SearchTypeMostActive',         // 1 << 5
    ], true); // SearchType as BitWise

    $search_type = SearchTypeMostRecent | SearchTypeMostActive;

    if($search_type & SearchTypeMostRecent) {
        // Search most recent files (will execute)
    }
    if($search_type & SearchTypePastWeek) {
        // Search files from the past will (will not execute)
    }

    if($search_type & SearchTypeMostActive) {
        // Search most active files AS WELL (will execute as well)
    }

Answer 2

不.

您必须使用数组,或者,如果您需要具有自定义类型的类,类和对象.