Instagram的.给定User_id,我如何找到用户名？

Question

我有一个包含数千个Instagram用户ID的列表.我如何获得他们的Instagram用户名/句柄？

谢谢

Answer 1

如果您没有批准的instagram应用程序,我建议使用这个php库:https: //github.com/postaddictme/instagram-php-scraper

$instagram = Instagram::withCredentials('username', 'password', 'path/to/cache/');
$account = $instagram->getAccountById('193886659');
echo $account->getUsername();

或直接访问:

https://www.instagram.com/query/?q=ig_user(3){id,username,external_url,full_name,profile_pic_url,biography,followed_by{count},follows{count},media{count},is_private,is_verified}

更新:此网址不再有效.你需要使用POST.请参阅回购以了解具体方法

Answer 2

您可以通过内部/user/端点instagram用于AJAX请求而无需API来访问它：

https://i.instagram.com/api/v1/users/{user_id}/info/

{user_id}像的数字用户ID 在哪里6817966272？

返回的响应示例（user['username']有关用户名，请参见键）：

获取https://i.instagram.com/api/v1/users/6817966272/info/

{
  "user": {
    "pk": 6817966272,
    "username": "myriaamaa",
    "full_name": "\u2661",
    "is_private": false,
    "profile_pic_url": "https://instagram.fcnx2-1.fna.fbcdn.net/vp/66486d198fc02046d04d7bc11e51e54a/5D913015/t51.2885-19/s150x150/61226760_298998544311382_2345929352031502336_n.jpg?_nc_ht=instagram.fcnx2-1.fna.fbcdn.net",
    "profile_pic_id": "2056076981860037983_6817966272",
    "is_verified": false,
    "has_anonymous_profile_picture": false,
    "media_count": 216,
    "follower_count": 4926,
    "following_count": 83,
    "following_tag_count": 0,
    "biography": "YOU. ARE. HOLY \ud83c\udf19",
    "external_url": "",
    "total_igtv_videos": 0,
    "total_ar_effects": 0,
    "usertags_count": 6,
    "is_favorite": false,
    "is_interest_account": true,
    "hd_profile_pic_versions": [
      {
        "width": 320,
        "height": 320,
        "url": "https://instagram.fcnx2-1.fna.fbcdn.net/vp/fafecdc76c82de85580c9c03d14b1aaa/5D9BD2E5/t51.2885-19/s320x320/61226760_298998544311382_2345929352031502336_n.jpg?_nc_ht=instagram.fcnx2-1.fna.fbcdn.net"
      },
      {
        "width": 640,
        "height": 640,
        "url": "https://instagram.fcnx2-1.fna.fbcdn.net/vp/0ec5339e3958c9c41414e5378fa2443c/5D7DD28A/t51.2885-19/s640x640/61226760_298998544311382_2345929352031502336_n.jpg?_nc_ht=instagram.fcnx2-1.fna.fbcdn.net"
      }
    ],
    "hd_profile_pic_url_info": {
      "url": "https://instagram.fcnx2-1.fna.fbcdn.net/vp/8b3859950f0bb8e1a4a8f65566992b78/5D9132EF/t51.2885-19/61226760_298998544311382_2345929352031502336_n.jpg?_nc_ht=instagram.fcnx2-1.fna.fbcdn.net",
      "width": 774,
      "height": 774
    },
    "mutual_followers_count": 0,
    "has_highlight_reels": true,
    "can_be_reported_as_fraud": false,
    "is_business": false,
    "account_type": 1,
    "is_call_to_action_enabled": null,
    "include_direct_blacklist_status": true,
    "is_potential_business": true,
    "is_bestie": false,
    "has_unseen_besties_media": false,
    "show_account_transparency_details": false,
    "auto_expand_chaining": false,
    "highlight_reshare_disabled": false
  },
  "status": "ok"
}

编辑2019-10：

该端点仅服务于将自己标识为instagram应用的用户代理。

我与iphone的instagram用户代理一起工作：

Mozilla/5.0 (iPhone; CPU iPhone OS 10_3_3 like Mac OS X) AppleWebKit/603.3.8 (KHTML, like Gecko) Mobile/14G60 Instagram 12.0.0.16.90 (iPhone9,4; iOS 10_3_3; en_US; en-US; scale=2.61; gamut=wide; 1080x1920)

有关更多信息，请查看此在线用户代理数据库：https : //developers.whatismybrowser.com/useragents/explore/software_name/instagram/1

# top 5:
Mozilla/5.0 (Linux; Android 8.1.0; motorola one Build/OPKS28.63-18-3; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/70.0.3538.80 Mobile Safari/537.36 Instagram 72.0.0.21.98 Android (27/8.1.0; 320dpi; 720x1362; motorola; motorola one; deen_sprout; qcom; pt_BR; 132081645)  
Mozilla/5.0 (Linux; Android 7.0; Lenovo K33b36 Build/NRD90N; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/65.0.3325.109 Mobile Safari/537.36 Instagram 41.0.0.13.92 Android (24/7.0; 480dpi; 1080x1920; LENOVO/Lenovo; Lenovo K33b36; K33b36; qcom; pt_BR; 103516666)  
Mozilla/5.0 (Linux; Android 5.0.1; LG-H342 Build/LRX21Y; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/65.0.3325.109 Mobile Safari/537.36 Instagram 40.0.0.14.95 Android (21/5.0.1; 240dpi; 480x786; LGE/lge; LG-H342; c50ds; c50ds; pt_BR; 102221277)  
Mozilla/5.0 (Linux; Android 6.0.1; SM-G610M Build/MMB29K; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/65.0.3325.109 Mobile Safari/537.36 Instagram 41.0.0.13.92 Android (23/6.0.1; 480dpi; 1080x1920; samsung; SM-G610M; on7xelte; samsungexynos7870; pt_BR; 103516666)  
Mozilla/5.0 (Linux; Android 8.0.0; SM-A520F Build/R16NW; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/66.0.3359.158 Mobile Safari/537.36 Instagram 46.0.0.15.96 Android (26/8.0.0; 480dpi; 1080x1920; samsung; SM-A520F; a5y17lte; samsungexynos7880; pt_BR; 109556226)

Answer 3

你必须使用这个Instagram API:

https://api.instagram.com/v1/users/{user-id}/?access_token=ACCESS-TOKEN

响应将包含用户名,全名,生物,关注者计数和其他信息.

但是,在您可以访问API之前,您必须获得Instagram批准的应用程序.

您可以尝试https://www.picodash.com,它允许您搜索ID并获取用户结果,但这将是一个逐个搜索并获取信息的手动过程

Answer 4

由于 Instagram 对其 API 的限制（我的意思是SandBox），在这种情况下使用 Instagram 官方 API 并不容易，所以我用 Python 编写了一个片段，将 Instagram 用户 ID 转换为用户名，反之亦然。

它使用 GraphQL API 从 Instagram 不受任何限制地获取信息。

[+] 由于 Instagram API 更改而更新代码 (30/5/2019)

import json
import requests
import re
import hashlib


def usernameToUserId(user):
    r1 = requests.get('https://www.instagram.com/web/search/topsearch/?query=' + user, headers={
        'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:64.0) Gecko/20100101 Firefox/64.0'}).text

    if json.loads(r1)['users'][0]['user']['username'] == user:
        return json.loads(r1)['users'][0]['user']['pk']


def useridToUsername(id):
    if str(id).isnumeric():
        r1 = requests.get('https://instagram.com/instagram/', headers={
            'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:64.0) Gecko/20100101 Firefox/64.0', }).text
        rhx_gis = json.loads(re.compile('window._sharedData = ({.*?});', re.DOTALL).search(r1).group(1))['nonce']

        ppc = re.search(r'ProfilePageContainer.js/(.*?).js', r1).group(1)
        r2 = requests.get('https://www.instagram.com/static/bundles/es6/ProfilePageContainer.js/' + ppc + '.js').text
        query_hash = re.findall(r'{value:!0}\);const o=\"(.*?)\"', r2)[0]

        query_variable = '{"user_id":"' + str(id) + '","include_reel":true}'
        t = rhx_gis + ':' + query_variable
        x_instagram_gis = hashlib.md5(t.encode("utf-8")).hexdigest()

        header = {'X-Instagram-GIS': x_instagram_gis,
                  'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:64.0) Gecko/20100101 Firefox/64.0',
                  'X-Requested-With': 'XMLHttpRequest'}
        r3 = requests.get(
            'https://www.instagram.com/graphql/query/?query_hash=' + query_hash + '&variables=' + query_variable,
            headers=header).text

        username = json.loads(r3)['data']['user']['reel']['user']['username']
        return username


#print(useridToUsername("1234567890"))
#print(usernameToUserId("TheUserName"))

Github 链接获取更多更新：https : //github.com/Snbig/InstaTrack