Code Golf:用最少的代码行打印整个"12 Days of Christmas"歌曲

fiz*_*zer 25 language-agnostic code-golf rosetta-stone

打印流行节日歌曲的所有12节经文.

在12 节经文中,我的意思是在歌曲中演唱的每一行的重复,即

第一节:在圣诞节的第一天,我的真爱给了我一棵梨树上的鹧..

第二节在圣诞节的第二天,我的真爱给了我两只斑鸠和一棵梨树上的鹧..

...

N:在圣诞节的第n天,我的真爱给了我(没有第一行的第N-1节)(第N行增加了一行)

fiz*_*zer 44

Common Lisp:

(mapc #'princ
      (reverse (maplist #'(lambda(l)
         (format nil 
            "On the ~:R day of Christmas my true love gave to me~%~{~a~%~}~%" 
                (length l) l)) 
    '("twelve drummers drumming,"
      "eleven pipers piping,"
      "ten lords a-leaping,"
      "nine ladies dancing,"
      "eight maids a-milking,"
      "seven swans a-swimming,"
      "six geese a-laying,"
      "five gold rings,"
      "four calling birds,"
      "three french hens,"
      "two turtle doves, and"
      "a partridge in a pear tree."))))
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编辑:

如果你取出空白,上面是412个字符.

这个:

(let ((g))
  (dotimes (i 12)
    (format t
        "On the ~:R day of Christmas my true love gave to me~%~{~R ~:*~
         ~[~;~;turtle doves and~;french hens,~;calling birds,~;gold rings,~
         ~;geese a-laying,~;swans a-swimming,~;maids a-milking,~
         ~;ladies dancing,~;lords a-leaping,~;pipers piping,~
         ~;drummers drumming,~]~%~}a partridge in a pear tree~2%"
        (1+ i) g)
    (push (+ i 2) g)))
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如果你在格式字符串中取出空格和〜引用的换行符,则为344个字符:

(let((g))(dotimes(i 12)(format t"On the ~:R day of Christmas my true love gave to me~%~{~R ~:*~[~;~;turtle doves and~;french hens,~;calling birds,~;gold rings,~;geese a-laying,~;swans a-swimming,~;maids a-milking,~;ladies dancing,~;lords a-leaping,~;pipers piping,~;drummers drumming,~]~%~}a partridge in a pear tree~2%"(1+ i)g)(push(+ i 2)g)))
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编辑:

看起来这个问题已经过去了,网站正在唠叨我接受一个答案.据我所知,这个是最短的.如果我接受自己的答案,我有点害怕该网站会做什么 - 可能会给我一个自恋者或自慰者徽章.

你无法接受自己的答案.很公平.我会把它打开.感谢大家的回应.


Jul*_*iet 37

使用F#:

#light
open System.Net; open System.Text.RegularExpressions
printf "%s" ((new WebClient()).DownloadString("http://www.textfiles.com/holiday/12-bugs")
    |> (fun x -> (new Regex("Lines: \d+\s+([\s\S]+)--")).Match(x).Groups.[1].Value))
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第二天产出:

For the twelfth bug of Christmas, my manager said to me
     Tell them it's a feature
     Say it's not supported
     Change the documentation
     Blame it on the hardware
     Find a way around it
     Say they need an upgrade
     Reinstall the software
     Ask for a dump
     Run with the debugger
     Try to reproduce it
     Ask them how they did it and
     See if they can do it again.

  • 但它很聪明. (10认同)
  • 我认为下载文本可能会延伸规则:) (4认同)
  • 尝试自己唱歌,但要确保你在第五名时独自一人. (3认同)

Bol*_*ait 27

不是我的,但很有趣......

这是http://en.wikipedia.org/wiki/Obfuscated_code(作者:James O. Coplien)的一个着名例子:

#include <stdio.h>
main(t,_,a)char *a;{return!0<t?t<3?main(-79,-13,a+main(-87,1-_,
main(-86,0,a+1)+a)):1,t<_?main(t+1,_,a):3,main(-94,-27+t,a)&&t==2?_<13?
main(2,_+1,"%s %d %d\n"):9:16:t<0?t<-72?main(_,t,
"@n'+,#'/*{}w+/w#cdnr/+,{}r/*de}+,/*{*+,/w{%+,/w#q#n+,/#{l,+,/n{n+,/+#n+,/#\
;#q#n+,/+k#;*+,/'r :'d*'3,}{w+K w'K:'+}e#';dq#'l \
q#'+d'K#!/+k#;q#'r}eKK#}w'r}eKK{nl]'/#;#q#n'){)#}w'){){nl]'/+#n';d}rw' i;# \
){nl]!/n{n#'; r{#w'r nc{nl]'/#{l,+'K {rw' iK{;[{nl]'/w#q#n'wk nw' \
iwk{KK{nl]!/w{%'l##w#' i; :{nl]'/*{q#'ld;r'}{nlwb!/*de}'c \
;;{nl'-{}rw]'/+,}##'*}#nc,',#nw]'/+kd'+e}+;#'rdq#w! nr'/ ') }+}{rl#'{n' ')# \
}'+}##(!!/")
:t<-50?_==*a?putchar(31[a]):main(-65,_,a+1):main((*a=='/')+t,_,a+1)
  :0<t?main(2,2,"%s"):*a=='/'||main(0,main(-61,*a,
"!ek;dc i@bK'(q)-[w]*%n+r3#l,{}:\nuwloca-O;m .vpbks,fxntdCeghiry"),a+1);}
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"虽然乍一看是难以理解的,但它是一个合法的C程序,在编译和运行时将生成12个圣诞节的12节经文.它包含了代码中内联编码形式的诗所需的所有字符串.迭代12天,显示它需要的东西."

虽然它不会赢得高尔夫,但它大约是830个字节.

  • @BoltBait:不,在我看来,同行评审会很短,很容易开始;-) (3认同)
  • main的递归使用在某种程度上很酷.之前从未见过. (3认同)

ann*_*ata 15

class TrueLove: ITrueLove 
{
  List<IPresent> give(int day) 
  {
    List<IPresent> lovesLabourLost = new List<IPresent>();

    //if this was C++ could you replace this with a Figgy Duff Device?
    for (int i=1; i<=day; i++)
    {
      if(day > 1 && i<=2) {lovesLabourLost .Add(new TurtleDove());}
      if(day > 2 && i<=3) {lovesLabourLost .Add(new FrenchHen());}
      if(day > 3 && i<=4) {lovesLabourLost .Add(new CallingBird());}
      if(day > 4 && i<=5) {lovesLabourLost .Add(new GOLDRING());}
      if(day > 5 && i<=6) {lovesLabourLost .Add(new LayingGeese());}
      if(day > 6 && i<=7) {lovesLabourLost .Add(new SwimmingSwan());}
      if(day > 7 && i<=8) {lovesLabourLost .Add(new MilikingMaid());}
      if(day > 8 && i<=9) {lovesLabourLost .Add(new DancingLady());}
      if(day > 9 && i<=10) {lovesLabourLost .Add(new LeapingLord());}
      if(day > 10 && i<=11) {lovesLabourLost .Add(new PipingPiper());}
      if(day > 11 && i<=12) {lovesLabourLost .Add(new DrummingDrummer());}
    }

    return lovesLabourLost && (new PartridgeInPearTree());
  }
}

static class Me: IDemanding
{
  static ITrueLove myTrueLove = new TrueLove();

  static List<IPresent> myPresents = new List<IPresent>();

  static void demandPresents()
  {
    for (int i=1; i<=daysOfChristmas; i++)
    {
      List<IPresent> MOAR = myTrueLove.give(i);

      foreach (IPresent another in MOAR)
      {
        myPresents.Add(another);
      }
    }
  }
}

const int daysOfChristmas = 12;

Me.demandPresents();
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  • 无论是关于C#的笑话,还是有人不知道如何打代码高尔夫:) (5认同)
  • 我已经投了票,因为我直接开玩笑看着假设女性和(失去的劳动之爱)喜欢Me.demandPresents() (2认同)

dsi*_*cha 15

在D编程语言中,使用switch语句落实:

import std.stdio;

void main() {
    for(uint i = 1; i < 13; i++) {
        writeln("On the ", i, " day of Christmas, my true love gave to me:");
        switch(i) {
            case 12:
                writeln("twelve drummers drumming,");
            case 11:
                writeln("eleven pipers piping,");
            case 10:
                writeln("ten lords a-leaping,");
            case 9:
                writeln("nine ladies dancing,");
            case 8:
                writeln("eight maids a-milking,");
            case 7:
                writeln("seven swans a-swimming,");
            case 6:
                writeln("six geese a-laying,");
            case 5:
                writeln("five gold rings,");
            case 4:
                writeln("four calling birds,");
            case 3:
                writeln("three french hens,");
            case 2:
                writeln("two turtle doves, and");
            case 1:
                writeln("a partridge in a pear tree.\n");
        }
    }
}
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str*_*ger 14

击:

wget -qO- http://tinyurl.com/a3xw8b
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我使用frizzer.myopenid.com的CLisp实现的输出作为开始.


Jas*_*ers 14

在C++中你是

std::cout << boost::12_days_of_christmas;
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  • 我讨厌挑选这样一个可爱的解决方案,但我很确定C++标识符不能以数字开头. (4认同)

Min*_*ras 11

C#,421个字符

var t="";for(int i=0;i++<12;)Console.Write("On the {0}{1} day of Christmas, my true love gave to me: {2}\n",i,i<2?"st":i<3?"nd":i<4?"rd":"th",t="|a partridge in a pear tree.|two turtle doves, and |three french hens,|four calling birds,|five gold rings|six geese a-lay@seven swans a-swimm@eight maids a-milk@nine ladies danc@ten lords a-leap@eleven pipers pip@twelve drummers drumm@".Replace("@","ing,|").Split('|')[i]+t);
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间隔版本:

var t="";

for(int i = 0; i++ < 12;)
    Console.Write("On the {0}{1} day of Christmas, my true love gave to me: {2}\n",
            i,
            i < 2 ? "st" : i < 3 ? "nd" : i < 4 ? "rd" : "th",
            t="|a partridge in a pear tree.
               |two turtle doves, and 
               |three french hens,
               |four calling birds,
               |five gold rings
               |six geese a-lay
               @seven swans a-swimm
               @eight maids a-milk
               @nine ladies danc
               @ten lords a-leap
               @eleven pipers pip
               @twelve drummers drumm@"
            .Replace("@","ing,|")
            .Split('|')[i]+t);
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Jas*_*ers 9

PHP:375个字符

$v=split(":",":a partridge in a pear tree.\n:two turtle doves, and:three french hens:four calling birds:five gold rings:six geese a-lay:seven swans a-swimm:eigth maids a-milk:nine ladies danc:ten lords a-leap:eleven pipers pip:twelve drummers drumm");while($i<12){?>On the <?=date(jS,$i*86400)," day of Christmas my true love gave to me",$s=", ".$v[++$i].($i>5?'ing':'').$s;}
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编辑:更新的可运行版本(377)字符

<?$v=split(":",":a partridge in a pear tree.\n:two turtle doves, and:three french hens:four calling birds:five gold rings:six geese a-lay:seven swans a-swimm:eigth maids a-milk:nine ladies danc:ten lords a-leap:eleven pipers pip:twelve drummers drumm");while($i<12){?>On the <?=date(jS,$i*86400)," day of Christmas my true love gave to me",$s=", ".$v[++$i].($i>5?'ing':'').$s;}
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jrc*_*cs3 7

VB.Net - 530个字符(无空格),634(空格)

Module ChristmasSong
    Sub Main()
        Dim i&, f$ : Dim d$() = {"first", "second", "third", "fourth", "fifth", "sixth", "seventh", "eighth", "ninth", "tenth", "eleventh", "twelfth"}, g$() = {"a partridge in a pear tree.", "two turtle doves, and ", "three french hens, ", "four calling birds, ", "five gold rings, ", "six geese a-laying, ", "seven swans a-swimming, ", "eigth maids a-milking, ", "nine ladies dancing, ", "ten lords a-leaping, ", "eleven pipers piping, ", "twelve drummers drumming, "}
        For i = 0 To 11 : f = g(i) & f : Console.WriteLine("On the {0} day of Christmas, my true love gave to me {1}", d(i), f) : Next
    End Sub
End Module
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Dan*_*ker 7

Linq到对象,580个字符(没有空格)

Console.WriteLine(Enumerable.Range(1, 13).SelectMany(day =>
    Enumerable.Repeat("\nOn the " + day + 
                      (day == 1 ? "st" : 
                      (day == 2 ? "nd" : 
                      (day == 3 ? "rd" : 
                      "th"))) + " day of Christmas my true love gave to me ", 1)
              .Concat((new []
                {
                    "twelve drummers drumming,",
                    "eleven pipers piping,",
                    "ten lords a-leaping,",
                    "nine ladies dancing,",
                    "eight maids a-milking,",
                    "seven swans a-swimming,",
                    "six geese a-laying,",
                    "five gold rings,",
                    "four calling birds,",
                    "three french hens,",
                    "two turtle doves, and",
                    "a partridge in a pear tree."
                }).Reverse().Take(day).Reverse()))
              .Aggregate((a, b) => a + "\n" + b));
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Ken*_*ric 6

Perl的.

use Lingua::EN::Numbers qw(num2en_ordinal);
print 'On the ', num2en_ordinal($_+1),' day of Christmas my true love gave to me, ', reverse(( split /\|/, "a partridge in a pear tree.\n|two turtle doves, and |three french hens, |four calling birds, |five gold rings, |six geese a-laying, |seven swans a-swimming, |eight maids a-milking, |nine ladies dancing, |ten lords a leaping, |eleven pipers piping, |twelve drummers drumming, ")[ 0 .. $_ ]) for 0 .. 11;
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(459个字符)

我想让它变得更好,更富有表现力,但这是一场高尔夫挑战.

这种风格有些违反了正确的编码标准.但那对你来说是高尔夫.

通用EN ::数量::

这是不太紧凑的版本,没有偷偷摸摸的技巧.

use Lingua::EN::Numbers qw(num2en_ordinal);
my @gifts = (
    'a partridge in a pear tree.',
    'two turtle doves, and ',
    'three french hens, ',
    'four calling birds, ',
    'five gold rings, ',
    'six geese a-laying, ',
    'seven swans a-swimming, ',
    'eight maids a-milking, ',
    'nine ladies dancing, ',
    'ten lords a leaping, ',
    'eleven pipers piping, ',
    'twelve drummers drumming, '
);
for my $verse_id ( 0 .. $#gifts ) {
    printf 'On the %s day of Christmas my true love gave to me, ', num2en_ordinal($verse_id +1);
    print reverse @verse[ 0 .. $verse_id ];
    print "\n";
}
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bd8*_*808 6

for d in range(12):print"On the %s day of Christmas, my true love gave to me\n\t%s\n"%("first|second|third|fourth|fifth|sixth|seventh|eighth|ninth|tenth|eleventh|twelfth".split("|")[d],"\n\t".join("twelve drummers drumming|eleven pipers piping|ten lords a-leaping|nine ladies dancing|eight maids a-milking|seven swans a-swimming|six geese a-laying|five gold rings|four calling birds|three french hens|two turtle doves and|a partridge in a pear tree.".split("|")[11-d:]))
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Python,422个字符


Kir*_*now 6

LilyPond,340个字符(比Common Lisp短)

"这是赛季!(而且非常合适,因为LilyPond主要用于排版音乐......除了歌词之外,人们可以轻松地调整此代码以生成乐曲的乐谱.)

改编自fizzer的解决方案.

#(map(lambda(x)(format #t"On the ~:R day of Christmas my true love gave to me~{ ~R~:*~[~;~;turtle doves and~;French hens,~;calling birds,~;gold rings,~;geese a-laying,~;swans a-swimming,~;maids a-milking,~;ladies dancing,~;lords a-leaping,~;pipers piping,~;drummers drumming,~]~} a partridge in a pear tree.
"x(iota(1- x)x -1)))(iota 12 1))
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用法: $ lilypond thisfile.ly

这个版本用341个字符完全匹配fizzer的输出,但缩短了三个字节:

#(map(lambda(x)(format #t"On the ~:R day of Christmas my true love gave to me~{
~R ~:*~[~;~;turtle doves and~;french hens,~;calling birds,~;gold rings,~;geese a-laying,~;swans a-swimming,~;maids a-milking,~;ladies dancing,~;lords a-leaping,~;pipers piping,~;drummers drumming,~]~}
a partridge in a pear tree

"x(iota(1- x)x -1)))(iota 12 1))
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Dan*_*man 5

红宝石.我认为这非常简洁(努力工作全部在一条线上):

days = %w{First Second Third Fourth Fifth Sixth Seventh Eighth Ninth Tenth Eleventh Twelfth}

presents = [
    "twelve drummers drumming",
    "eleven pipers piping",
    "ten lords a leaping",
    "nine ladies dancing",
    "eight maids a-milking",
    "seven swans a-swimming",
    "six geese a-laying",
    "five gold rings",
    "four calling birds",
    "three french hens",
    "two turtle doves, and",
    "a partridge in a pear tree"
    ]

0.upto(11) { |i| 
    puts "On the #{days[i]} of Christmas my true love gave to me " + presents.last(i+1).join(", ")
}
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