使用JSON_VALUE访问SQL Server 2016中的JSON数组

UVD*_*ata 8 sql sql-server json sql-server-2016

我在使用新引入的JSON_VALUE函数访问json中的数组时遇到困难.请考虑以下代码 -

IF EXISTS(SELECT 1 FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME='JsonData')
    DROP TABLE JsonData;
go

CREATE TABLE JsonData(JsonData nvarchar(max));
DECLARE @SQL nvarchar(max);
DECLARE @Table AS TABLE(JsonPath VARCHAR(256));

INSERT INTO JsonData(JsonData)
VALUES(
'{
  "firstName": "John",
  "lastName" : "doe",
  "age"      : 26,
  "address"  : {
    "streetAddress": "naist street",
    "city"         : "Nara",
    "postalCode"   : "630-0192"
  },
  "phoneNumbers": [
    {
      "type"  : "iPhone",
      "number": "0123-4567-8888"
    },
    {
      "type"  : "home",
      "number": "0123-4567-8910"
    }
  ]
}')


INSERT INTO @Table
SELECT VALUE  FROM OPENJSON('{
"Path1":"$.firstName","Path2":"$.phoneNumbers[:1].number"
}') ;

SELECT  @SQL=(SELECT 'UNION SELECT '''+ CAST(JsonPath AS VARCHAR(256)) +''',JSON_VALUE(JsonData,'''+a.JsonPath+''')  
                    FROM JsonData a'                             
                    FROM @Table a       
        FOR XML PATH(''), TYPE)
    .value('.','NVARCHAR(MAX)')
FROM @Table t;

SELECT @SQL=RIGHT(@SQL,LEN(@SQL)-5)

PRINT @SQL    

EXEC SP_EXECUTESQL @SQL;
Run Code Online (Sandbox Code Playgroud)

这里如果我想访问特定的电话号码,则访问此节点的常用语法不起作用.我在这种情况下遇到以下错误

JSON path is not properly formatted. Unexpected character ':' is found at position 15.
Run Code Online (Sandbox Code Playgroud)

虽然当我在http://jsonpath.com上查看时,我能够检索到价值.SQL Server 2016是否使用一些不同的语法来访问JSON值?

小智 10

从phoneNumbers获取所有内容:

DECLARE @json nvarchar(max)=
    '{
      "firstName": "John",
      "lastName" : "doe",
      "age"      : 26,
      "address"  : {
        "streetAddress": "naist street",
        "city"         : "Nara",
        "postalCode"   : "630-0192"
      },
      "phoneNumbers": [
        {
          "type"  : "iPhone",
          "number": "0123-4567-8888"
        },
        {
          "type"  : "home",
          "number": "0123-4567-8910"
        }
      ]
    }'

    SELECT [Type], [Number]
    FROM OPENJSON( @json, '$.phoneNumbers' ) 
    WITH ([Type] NVARCHAR(25) '$.type', [Number] NVARCHAR(25) '$.number');
Run Code Online (Sandbox Code Playgroud)


Boc*_*Lin 9

您可以使用"CROSS APPLY"来获取firstName的电话号码:

SELECT  JSON_VALUE (jsonData, '$.firstName'),p.*
    FROM JsonData
    CROSS APPLY
    OPENJSON (JsonData, '$.phoneNumbers') WITH(type varchar(10) '$.type', number varchar (30) '$.number') p
Run Code Online (Sandbox Code Playgroud)


小智 5

SQL Server 2016 支持 JSON。它非常相似,几乎完全相同。你会自己做比较。

您不需要使用临时变量 @Table 然后进行操作...

只需运行以下查询

SELECT  JSON_VALUE( JsonData, '$.phoneNumbers[0].type' ) AS [PhoneType], 
        JSON_VALUE( JsonData, '$.phoneNumbers[0].number' ) AS [PhoneNumber]
FROM JsonData
WHERE ISJSON( JsonData ) > 0;
--iPhone 0123-4567-8888

SELECT  JSON_VALUE( JsonData, '$.phoneNumbers[1].type' ) AS [PhoneType], 
        JSON_VALUE( JsonData, '$.phoneNumbers[1].number' ) AS [PhoneNumber]
FROM JsonData
WHERE ISJSON( JsonData ) > 0;
--home  0123-4567-8910
Run Code Online (Sandbox Code Playgroud)

查看 Microsoft 的这些官方链接,了解有关 JSON 支持的更多详细信息:

https://msdn.microsoft.com/en-us/library/dn921897.aspx

https://msdn.microsoft.com/en-us/library/dn921898.aspx