SQL：仅选择表中具有相同值的一行

Question

我对 sql 有点陌生，对于我的项目，我需要做一些数据库排序和过滤：

假设我的数据库如下所示：

==========================================
|  id       |       email        | name
==========================================
|   1       |  123@test.com      | John
|   2       |  234@test.com      | Peter
|   3       |  234@test.com      | Steward
|   4       |  123@test.com      | Ethan
|   5       |  542@test.com      | Bob
|   6       |  123@test.com      | Patrick
==========================================

我应该怎么做才能只返回具有相同电子邮件地址的最后一列：

==========================================
|  id       |       email        | name
==========================================
|   3       |  234@test.com      | Steward
|   5       |  542@test.com      | Bob
|   6       |  123@test.com      | Patrick
==========================================

提前致谢！

Answer 1

SQL查询：

    SELECT * FROM test.test1  WHERE id IN (
  SELECT MAX(id) FROM test.test1 GROUP BY email
);

希望这能解决您的问题。谢谢。

Answer 2

这是一个更清晰的方法：

SELECT *
FROM table
ORDER BY email DESC
LIMIT 1;