mrl*_*sen 3 javascript svg d3.js reactjs
使用 d3 和 React 我绘制了一条路径。在这条路径上,我有多个圆圈,只能沿着该路径拖动。然而,我当前的实现仅(在某种程度上)在该路径上有一个圆圈时才起作用。
(在 DragStart 上,无论位置如何,它都会在路径上移动到长度 0,并且每当我拖动第二个圆时,它都会从前一个圆的位置开始)。
我的问题是:如何沿着 d3 中的路径拖动多个圆圈(或我们)?有没有办法根据当前圆的 cx 和 cy 获取路径上的 currentLength 位置?
var currentLength = 0;
class MyComponent extends Component {
constructor(props) {
super(props)
currentLength = 0;
}
componentDidMount() {
var drag = d3.behavior.drag()
.on('drag', this.move);
var g = d3.select(this._base);
var circle = g.selectAll('circle').data(this.props.data);
var onEnter = circle.enter();
onEnter.append('circle')
.attr({
r: 10,
cx: (d) => d.x,
cy: (d) => d.y
})
.style('fill', 'blue')
.call(drag);
}
move(d) {
currentLength += d3.event.dx + d3.event.dy
if (currentLength < 0) {
currentLength = 0
}
var pointAtCurrentLength = d3.select('#path').node().getPointAtLength(currentLength)
this.cx.baseVal.value = pointAtCurrentLength.x;
this.cy.baseVal.value = pointAtCurrentLength.y;
}
render() {
return <g ref={(c)=>this._base=c}></g>
}
}Run Code Online (Sandbox Code Playgroud)
与此类似的东西,只能拖动和多个圆圈: http://bl.ocks.org/mbostock/1705868
这是对此示例的快速修改,使圆圈可拖动:
<!DOCTYPE html>
<meta charset="utf-8">
<style>
path {
fill: none;
stroke: #000;
stroke-width: 1.5px;
}
line {
fill: none;
stroke: red;
stroke-width: 1.5px;
}
circle {
fill: red;
}
</style>
<body>
<script src="//d3js.org/d3.v3.min.js"></script>
<script>
var points = [[600,276],[586,393],[378,388],[589,148],[346,227],[365,108]];
var width = 960,
height = 500;
var line = d3.svg.line()
.interpolate("cardinal");
var drag = d3.behavior.drag()
.on("drag", dragged);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var path = svg.append("path")
.datum(points)
.attr("d", line);
var line = svg.append("line");
var circle = svg.append("circle")
.attr("transform", "translate(" + points[0] + ")")
.attr("r", 7)
.call(drag);
svg.append("circle")
.attr("transform", "translate(" + points[5] + ")")
.attr("r", 7)
.call(drag);
function dragged(d) {
var m = d3.mouse(svg.node()),
p = closestPoint(path.node(), m);
d3.select(this)
.attr("transform", "translate(" + p[0] + "," + p[1] + ")")
}
function closestPoint(pathNode, point) {
var pathLength = pathNode.getTotalLength(),
precision = 8,
best,
bestLength,
bestDistance = Infinity;
// linear scan for coarse approximation
for (var scan, scanLength = 0, scanDistance; scanLength <= pathLength; scanLength += precision) {
if ((scanDistance = distance2(scan = pathNode.getPointAtLength(scanLength))) < bestDistance) {
best = scan, bestLength = scanLength, bestDistance = scanDistance;
}
}
// binary search for precise estimate
precision /= 2;
while (precision > 0.5) {
var before,
after,
beforeLength,
afterLength,
beforeDistance,
afterDistance;
if ((beforeLength = bestLength - precision) >= 0 && (beforeDistance = distance2(before = pathNode.getPointAtLength(beforeLength))) < bestDistance) {
best = before, bestLength = beforeLength, bestDistance = beforeDistance;
} else if ((afterLength = bestLength + precision) <= pathLength && (afterDistance = distance2(after = pathNode.getPointAtLength(afterLength))) < bestDistance) {
best = after, bestLength = afterLength, bestDistance = afterDistance;
} else {
precision /= 2;
}
}
best = [best.x, best.y];
best.distance = Math.sqrt(bestDistance);
return best;
function distance2(p) {
var dx = p.x - point[0],
dy = p.y - point[1];
return dx * dx + dy * dy;
}
}
</script>Run Code Online (Sandbox Code Playgroud)
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