从Mocked方法中返回一个模拟

Question

我不确定我会怎么做.

鉴于我有

public interface IFactory<T> where T : new()
{
    IWrapper<T> GetT(string s);
}

public interface IWrapper<out T> where T : new()
{
    void Execute(Action<T> action);
}

当我这样做

public class MoqTest
{
    public void test()
    {
        Mock<IWrapper<basicClass>> wrapperMock = new Mock<IWrapper<basicClass>>();
        Mock<IFactory<basicClass>> factoryMock = new Mock<IFactory<basicClass>>()
            .Setup(p => p.GetT(It.IsAny<string>()))
            .Returns(wrapperMock.Object);
    }
}

我明白了

无法隐式转换 Moq.Language.Flow.IReturnsResult<TestNamespace.IFactory<TestNamespace.basicClass>> 为Moq.Mock<TestNamespace.IFactory<TestNamespace.basicClass>>.存在显式转换(您是否错过了演员？)

请注意,这些只是模拟的示例对象.

它似乎不考虑返回类型等价.一个是a IReturnResult,另一个是aMoq.Mock

Answer 1

您的问题基本上是您将调用Returns方法的结果分配给factoryMock变量.

您想首先创建模拟并将其分配给factoryMock变量,然后像这样设置模拟:

Mock<IWrapper<basicClass>> wrapperMock = new Mock<IWrapper<basicClass>>();
Mock<IFactory<basicClass>> factoryMock = new Mock<IFactory<basicClass>>();

factoryMock
    .Setup(p => p.GetT(It.IsAny<string>()))
    .Returns(wrapperMock.Object);