在Swift中创建一个字典

mik*_*sis 12 dictionary ios parse-platform swift

我有一个取自Parse的对象,我想将其列保存到一个Dictionary或其他东西(如果它更好).

我想要这样的字典: ["name" : "Mike", "lastname" : "vorisis", "id" : "advsas"]

以下是我用来获取结果的代码:

func queryEvents() {
    let query = PFQuery(className: "eventController")
    query.limit = 1000
    query.includeKey("idEvent")
    query.includeKey("eventType")
    query.includeKey("idEvent.idMagazi")
    query.findObjectsInBackgroundWithBlock { (objects, error)-> Void in
        if let objects = objects  {
            for object in objects {
                var post = object["idEvent"] as? PFObject
                var post2 = post!["idMagazi"]
                print("retrieved related post: \(post2["name"]!)")
            }
        }
    }
}
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vad*_*ian 5

其他东西(如果它更好)是一个自定义类.将类型更改为idMagazi实际类型.

class Event {

  let post : PFObject
  let name : String
  let idMagazi : String

  init(object : PFObject) {
    self.post = object
    self.name = object["name"] as! String
    self.idMagazi = object["idMagazi"] as! String

  }
}
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并使用它

 ...
 if let objects = objects as? [PFObject]  {
    var events = [Event]()
    for object in objects {

      let post = Event(object: object)
      events.append(post)
      print("retrieved related post: \(post.name)")
    }
 }
 ...
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red*_*t84 5

在 SwiftDictionary<T,V>中相当于[T: V]. 如果未明确声明,则推断类型。

空字典创建(全部等效):

var dict1: Dictionary<String, String> = [:]
var dict2: [String: String] = [:]
var dict3 = Dictionary<String, String>()
var dict4 = [String: String]()
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带值的字典(全部等效):

var dict5 = ["Foo": "Bar", "Foo1": "Bar1", "Foo2": "Bar2"]
var dict6: Dictionary<String, String> = ["Foo": "Bar", "Foo1": "Bar1", "Foo2": "Bar2"]
var dict7: [String: String] = ["Foo": "Bar", "Foo1": "Bar1", "Foo2": "Bar2"]
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将值添加到现有字典:

dict["Foo"] = "Bar"
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在您的特定场景中,您可以使用这个:

let dict = ["name" : name, "lastname" : lastname , "id" : id]
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其中namelastnameidString变量。


根据您自己的答案进行更新:

有这个结构:

struct Event {
    var nameEvent: String
    var nameMagazi: String
}
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您可以使用这种方法,避免使用外部索引并使用数组而不是字典来存储结果。

var events: [Event]?

guard let objects = objects else { return }
events = objects.map { object in
    let post = object["idEvent"] as? PFObject
    let post2 = post!["idMagazi"] as? PFObject

    let nameEvent = post!["name"] as! String
    let idEvent = post?.objectId
    let nameMagazi = post2!["name"] as! String

    return Event(nameEvent: nameEvent , nameMagazi: nameMagazi)
}
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mik*_*sis 5

我终于找到了我该怎么做.

我使用一个结构与我想要的东西:

var userDictionary = [Int : Event]()
struct Event {
        var nameEvent: String
        var nameMagazi: String


    }
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然后我用这个:

  if let objects = objects  {
                for object in objects {

                    let post = object["idEvent"] as? PFObject
                    let post2 = post!["idMagazi"] as? PFObject

                    let nameEvent = post!["name"] as! String
                    let idEvent = post?.objectId
                    let nameMagazi = post2!["name"] as! String

                     self.events[self.i] = Event(nameEvent: nameEvent , nameMagazi: nameMagazi)

                    self.i += 1
                }
                print(self.events[1]!.nameEvent)
            }
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谢谢大家的答案!