如何将NSinteger转换为String

Question

我想在目标c中将int转换为字符串如何做到这一点.

我的代码.

for (i=0; i<=200; i=i+10) {
    // here i want to convet the value of i into string how to do this 

}   

提前致谢.

Answer 1

试试这个:

NSMutableString *myWord = [[NSMutableString alloc] init];
for (int i=0; i<=200; i=i+10) {
    [myWord appendString:[NSString stringWithFormat:@"%d", i]];
    //...
}
//do something with myWord...
[myWord release];

NSInteger是一个简单的typedef到int或long上64分之32位系统的数据类型.

Answer 2

NSInteger n = 13;
NSString string = @(n).stringValue;

参考文献参见Objective-C文字 - 文字删除了许多丑陋的样板代码,使你的代码库变得混乱:http://clang.llvm.org/docs/ObjectiveCLiterals.html