我有以下数据:
{"action":"CREATE","docs":1,"date":"2016 Jun 26 12:00:12","userid":"1234"}
{"action":"REPLACE","docs":2,"date":"2016 Jun 27 12:00:12","userid":"1234"}
{"action":"REPLACE","docs":1,"date":"2016 Jun 27 13:00:12","userid":"1234"}
{"action":"CREATE","docs":1,"date":"2016 Jun 28 12:00:12","userid":"3431"}
{"action":"REPLACE","docs":2,"date":"2016 Jun 28 13:00:12","userid":"3431"}
{"action":"CREATE","docs":1,"date":"2016 Jun 29 12:00:12","userid":"9999"}
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为了按日期(降序)获取每个唯一用户订单的记录,我使用了如下所示的Top Hits:
"aggs": {
"user_bucket": {
"terms": {
"field": "userid"
},
"aggs": {
"user_latest_count": {
"top_hits": {
"size": 1,
"sort": [
{
"data": {
"order": "desc"
}
}
],
"_source": {
"include": [
"docs"
]
}
}
}
}
}
}
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以上查询的结果如下:
{"action":"REPLACE","docs":1,"date":"2016 Jun 27 13:00:12","userid":"1234"}
{"action":"REPLACE","docs":2,"date":"2016 Jun 28 13:00:12","userid":"3431"}
{"action":"CREATE","docs":1,"date":"2016 Jun 29 12:00:12","userid":"9999"}
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现在,我想进一步聚合这个,结果如下:
{"sum_of_different_buckets": 4}
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但不知道如何SUM领域的" 文档从上面获得的结果"值.
小智 0
您还可以在聚合内任意嵌套聚合,以从数据中提取所需的汇总数据。可能是下面的示例作品。
"aggs" : {
"sum_of_different_buckets" : { "sum" : { "field" : "docs" } }
}
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