有没有一种简单的方法可以将序数字符串转换为匹配的数值？

Question

有没有人知道将"第一","第十"和"第一百"之类的单词转换为数字等价的方法？

样品:"第一" - > 1,"第二" - > 2,"第十" - > 10,"百分之一" - > 100

任何算法都足够了,但我在C#中写这个.

编辑

它不漂亮,一次只能用一个单词,但它适合我的目的.也许有人可以改进它,但我没时间.

 public static int GetNumberFromOrdinalString(string inputString)
    {
        string[] ordinalNumberWords = { "", "first", "second", "third", "fourth", "fifth", "sixth", "seventh", "eighth", "ninth", "tenth", "eleventh", "twelfth", "thirteenth", "fourteenth", "fifteenth", "sixteenth", "seventeenth", "eighteenth", "nineteenth", "twentieth" };
        string[] ordinalNumberWordsTens = { "", "tenth", "twentieth", "thirtieth", "fortieth", "fiftieth", "sixtieth", "seventieth", "eightieth", "ninetieth" };
        string[] ordinalNumberWordsExtended = {"hundredth", "thousandth", "millionth", "billionth" };

        if (inputString.IsNullOrEmpty() || inputString.Length < 5 || inputString.Contains(" ")) return 0;

        if (ordinalNumberWords.Contains(inputString) || ordinalNumberWordsTens.Contains(inputString))
        {
            var outputMultiplier = ordinalNumberWords.Contains(inputString) ? 1 : 10;
            var arrayToCheck = ordinalNumberWords.Contains(inputString) ? ordinalNumberWords : ordinalNumberWordsTens;

            // Use the loop counter to get our output integer.
            for (int x = 0; x < arrayToCheck.Count(); x++)
            {
                if (arrayToCheck[x] == inputString)
                {
                    return x * outputMultiplier;
                }
            }
        }

        // Check if the number is one of our extended numbers and return the appropriate value.
        if (ordinalNumberWordsExtended.Contains(inputString))
        {
            return inputString == ordinalNumberWordsExtended[0] ? 100 : inputString == ordinalNumberWordsExtended[1] ? 1000 : inputString == ordinalNumberWordsExtended[2] ? 1000000 : 1000000000;
        }

        return 0;
    }

Answer 1

除了我知道“和”这个词应该是从整数到小数的过渡之外，我从未考虑过这么多。喜欢

一百九十九美元十美分

不是

一百九十九美元。

无论如何，任何潜在的解决方案都必须解析输入字符串，引发任何异常或以其他方式返回值。

但首先你必须了解“规则” 这似乎非常武断并且基于传统，但这位先生似乎是一个很好的起点：

询问数学博士