Art*_*hur 1 .net c# floating-point precision
我是C#的新手,我无法理解,为什么我的变量不想增加到值,大于16777215.
我有代码:
float fullPerc = 100;
float bytesRead = 1;
long fileSize = 1;
ProgressBar pb1;
int blockSizeBytes = 0;
float counter = 0;
using (FileStream inFs = new FileStream(inFile, FileMode.Open))
{
fileSize = inFs.Length;
do
{
counter = counter + 1;
if (counter > 16777215) //&& counter < 16777230)
{
counter = counter + 10;
//Console.WriteLine(((counter + 10) /100));
}
count = inFs.Read(data, 0, blockSizeBytes);
offset += count;
outStreamEncrypted.Write(data, 0, count);
bytesRead += blockSizeBytes;
}
while (count > 0);
inFs.Close();
}
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当计数器的值等于16777216时,变量增量的counter = counter + 1;代码不起作用,但此代码
if (counter > 16777215) //&& counter < 16777230)
{
counter = counter + 10;
//Console.WriteLine(((counter + 10) /100));
}
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工作正常.
即,如果我评论此if代码,我counter将增长到16777216值,并将停止此值.当此变量> = 16777216时,仅增加10将增加此变量.
为什么?
你有尾数溢出,结果是一个presision损失.float(或Single)类型有24位尾数(最多16777216):
https://en.wikipedia.org/wiki/Single-precision_floating-point_format
让我们看看发生了什么:
private static String MakeReport(float value) {
return String.Join(" ", BitConverter
.GetBytes(value)
.Select(b => Convert.ToString(b, 2).PadLeft(8, '0')));
}
...
float f = 16777215;
// Mantissa (first 3 bytes) is full of 1's except the last one bit
// 11111111 11111111 01111111 01001011
Console.Write(MakeReport(f));
// Overflow! Presision loss
// 00000000 00000000 10000000 01001011
Console.Write(MakeReport(f + 1));
// Overflow! Presision loss
// 00000000 00000000 10000000 01001011
Console.Write(MakeReport(f + 2));
// Overflow! Presision loss
// 00000100 00000000 10000000 01001011
Console.Write(MakeReport(f + 10));
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解决办法:不使用浮动点为counter,但整数:
int counter = 0;
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避免整数除法转换成值double
float x = (float) ((((double)counter * blockSizeBytes) / fileSize) * fullPerc);
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