基于Spring MVC注释的多模块项目配置

Question

我实现了两个基于maven的独立Web项目,使用Spring MVC,hibernate和Jax-RS实现.但是我的要求发生了变化,现在我需要将项目作为子项目合并到另一个项目中,这是我们的父项目.所以我使用maven multimodule配置.

项目1:家长项目

<packaging>pom</packaging>
    <modules>
        <module>../child1</module>
        <module>../child2</module>
    </modules>

孩子1:

<packaging>jar</packaging>
    <parent>
        <groupId>com.xyz.alpha</groupId>
        <artifactId>parent</artifactId>
        <version>0.0.1-SNAPSHOT</version>
        <relativePath>../parent</relativePath>
    </parent>

孩子2:

    <packaging>jar</packaging>

    <dependency>
            <groupId>com.xyz.alpha</groupId>
            <artifactId>child1</artifactId>
            <version>2.0.2</version>
    </dependency>
    <parent>
        <groupId>com.xyz.alpha</groupId>
        <artifactId>parent</artifactId>
        <version>0.0.1-SNAPSHOT</version>
        <relativePath>../parent</relativePath>
    </parent>

但我需要在java中配置项目,以便它将扫描父项的组件以及子项目和执行项目.目前我对每个项目都有单独的配置:

AppIntializer.java

public class AppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class[] { AppConfig.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return null;
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/" };
    }
}

AppConfig.java

@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "com.x.y")
public class AppConfig extends WebMvcConfigurerAdapter{


    @Bean
    public ViewResolver viewResolver() {
        InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
        viewResolver.setViewClass(JstlView.class);
        viewResolver.setPrefix("/WEB-INF/views/");
        viewResolver.setSuffix(".jsp");
        return viewResolver;
    }

    @Override
    public void addCorsMappings(CorsRegistry registry) {
        registry.addMapping("/**");
    }

    @Override
    public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
        configurer.enable();
    }

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");


    }

}

HibernateConfiguration.java

@Configuration
@EnableTransactionManagement
@ComponentScan({ "com.x.y.configuration" })
@PropertySource(value = { "classpath:application.properties" })
public class HibernateConfiguration {

    @Autowired
    private Environment environment;

    @Bean
    public LocalSessionFactoryBean sessionFactory() {
        LocalSessionFactoryBean sessionFactory = new LocalSessionFactoryBean();
        sessionFactory.setDataSource(dataSource());
        sessionFactory.setPackagesToScan(new String[] { "com.x.y.model" });
        sessionFactory.setHibernateProperties(hibernateProperties());
        return sessionFactory;
     }

    @Bean
    public DataSource dataSource() {
        DriverManagerDataSource dataSource = new DriverManagerDataSource();
        dataSource.setDriverClassName(environment.getRequiredProperty("jdbc.driverClassName"));
        dataSource.setUrl(environment.getRequiredProperty("jdbc.url"));
        dataSource.setUsername(environment.getRequiredProperty("jdbc.username"));
        dataSource.setPassword(environment.getRequiredProperty("jdbc.password"));
        return dataSource;
    }

    private Properties hibernateProperties() {
        Properties properties = new Properties();
        properties.put("hibernate.dialect", environment.getRequiredProperty("hibernate.dialect"));
        properties.put("hibernate.show_sql", environment.getRequiredProperty("hibernate.show_sql"));
        properties.put("hibernate.format_sql", environment.getRequiredProperty("hibernate.format_sql"));
        properties.put("hibernate.hbm2ddl.auto", environment.getRequiredProperty("hibernate.hbm2ddl.auto"));
        return properties;        
    }

    @Bean
    @Autowired
    public HibernateTransactionManager transactionManager(SessionFactory s) {
       HibernateTransactionManager txManager = new HibernateTransactionManager();
       txManager.setSessionFactory(s);
       return txManager;
    }
}

Answer 1

第二个模块如果是 spring Mvc 或任何 web 应用程序模块，那么它应该具有第一个模块的依赖关系。下面起草一个示例结构，希望这会有所帮助：

child1 pom：

<parent>
    <groupId>com.xyz.alpha</groupId>
    <artifactId>parent</artifactId>
    <version>0.0.1-SNAPSHOT</version>
</parent>
<artifactId>child1-app</artifactId>
<packaging>jar</packaging>
<build>
</build>
<dependencies>
</dependencies>

child2 pom：

<parent>
    <groupId>com.xyz.alpha</groupId>
    <artifactId>parent</artifactId>
    <version>0.0.1-SNAPSHOT</version>
</parent>
<artifactId>child2-Webapp</artifactId>
<packaging>war</packaging>
<build>
</build>
<dependencies>
    <dependency>
        <groupId>org.sonatype.mavenbook.multi</groupId>
        <artifactId>child1-app</artifactId>
        <version>1.0</version>
      </dependency>
</dependencies>

另外，您可以根据应用程序配置中的 Hibernate 配置进行连接，例如：

@Import({HibernateConfiguration.class})
@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "com.x.y")
public class AppConfig extends WebMvcConfigurerAdapter{
    @Bean
    public ViewResolver viewResolver() {
        InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
        viewResolver.setViewClass(JstlView.class);
        viewResolver.setPrefix("/WEB-INF/views/");
        viewResolver.setSuffix(".jsp");
        return viewResolver;
    }

    @Override
    public void addCorsMappings(CorsRegistry registry) {
        registry.addMapping("/**");
    }

    @Override
    public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
        configurer.enable();
    }

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");
    }
}