如何通过innerText获取元素

Question

如果我知道文本标签包含什么,如何在html页面中获取标签.例如:

<a ...>SearchingText</a>

Answer 1

你必须手工遍历.

var aTags = document.getElementsByTagName("a");
var searchText = "SearchingText";
var found;

for (var i = 0; i < aTags.length; i++) {
  if (aTags[i].textContent == searchText) {
    found = aTags[i];
    break;
  }
}

// Use `found`.

Answer 2

您可以使用xpath来完成此任务

var xpath = "//a[text()='SearchingText']";
var matchingElement = document.evaluate(xpath, document, null, XPathResult.FIRST_ORDERED_NODE_TYPE, null).singleNodeValue;

您还可以使用此xpath搜索包含某些文本的元素:

var xpath = "//a[contains(text(),'Searching')]";

Answer 3

你可以使用jQuery :contains()选择器

var element = $( "a:contains('SearchingText')" );

Answer 4

使用目前最现代的语法,它可以非常干净地完成,如下所示:

for (const a of document.querySelectorAll("a")) {
  if (a.textContent.includes("your search term")) {
    console.log(a.textContent)
  }
}

或者使用单独的过滤器:

[...document.querySelectorAll("a")]
   .filter(a => a.textContent.includes("your search term"))
   .forEach(a => console.log(a.textContent))

当然,传统浏览器不会处理此问题,但如果需要传统支持,您可以使用转换器.

Answer 5

虽然已经有一段时间了,而且你已经(很久以来)接受了答案,但我认为我会提供更新的方法:

function findByTextContent(needle, haystack, precise) {
  // needle: String, the string to be found within the elements.
  // haystack: String, a selector to be passed to document.querySelectorAll(),
  //           NodeList, Array - to be iterated over within the function:
  // precise: Boolean, true - searches for that precise string, surrounded by
  //                          word-breaks,
  //                   false - searches for the string occurring anywhere
  var elems;

  // no haystack we quit here, to avoid having to search
  // the entire document:
  if (!haystack) {
    return false;
  }
  // if haystack is a string, we pass it to document.querySelectorAll(),
  // and turn the results into an Array:
  else if ('string' == typeof haystack) {
    elems = [].slice.call(document.querySelectorAll(haystack), 0);
  }
  // if haystack has a length property, we convert it to an Array
  // (if it's already an array, this is pointless, but not harmful):
  else if (haystack.length) {
    elems = [].slice.call(haystack, 0);
  }

  // work out whether we're looking at innerText (IE), or textContent 
  // (in most other browsers)
  var textProp = 'textContent' in document ? 'textContent' : 'innerText',
    // creating a regex depending on whether we want a precise match, or not:
    reg = precise === true ? new RegExp('\\b' + needle + '\\b') : new RegExp(needle),
    // iterating over the elems array:
    found = elems.filter(function(el) {
      // returning the elements in which the text is, or includes,
      // the needle to be found:
      return reg.test(el[textProp]);
    });
  return found.length ? found : false;;
}


findByTextContent('link', document.querySelectorAll('li'), false).forEach(function(elem) {
  elem.style.fontSize = '2em';
});

findByTextContent('link3', 'a').forEach(function(elem) {
  elem.style.color = '#f90';
});

<ul>
  <li><a href="#">link1</a>
  </li>
  <li><a href="#">link2</a>
  </li>
  <li><a href="#">link3</a>
  </li>
  <li><a href="#">link4</a>
  </li>
  <li><a href="#">link5</a>
  </li>
</ul>

当然,更简单的方法仍然是:

var textProp = 'textContent' in document ? 'textContent' : 'innerText';

// directly converting the found 'a' elements into an Array,
// then iterating over that array with Array.prototype.forEach():
[].slice.call(document.querySelectorAll('a'), 0).forEach(function(aEl) {
  // if the text of the aEl Node contains the text 'link1':
  if (aEl[textProp].indexOf('link1') > -1) {
    // we update its style:
    aEl.style.fontSize = '2em';
    aEl.style.color = '#f90';
  }
});

<ul>
  <li><a href="#">link1</a>
  </li>
  <li><a href="#">link2</a>
  </li>
  <li><a href="#">link3</a>
  </li>
  <li><a href="#">link4</a>
  </li>
  <li><a href="#">link5</a>
  </li>
</ul>

参考文献:

• Array.prototype.filter().
• Array.prototype.forEach().
• Array.prototype.slice().
• 条件('三元' assessment ? ifTrue : ifFalse)运算符.
• Function.prototype.call().
• typeof运营商.

Answer 6

功能方法.返回所有匹配元素的数组,并在检查时修剪周围的空格.

function getElementsByText(str, tag = 'a') {
  return Array.prototype.slice.call(document.getElementsByTagName(tag)).filter(el => el.textContent.trim() === str.trim());
}

用法

getElementsByText('Text here'); // second parameter is optional tag (default "a")

如果你正在查看不同的标签,例如跨度或按钮

getElementsByText('Text here', 'span');
getElementsByText('Text here', 'button');

对于旧浏览器,默认值tag ='a'将需要Babel

Answer 7

只需将您的子字符串传递到以下行：

外部 HTML

document.documentElement.outerHTML.includes('substring')

内部 HTML

document.documentElement.innerHTML.includes('substring')

您可以使用这些来搜索整个文档并检索包含搜索词的标签：

function get_elements_by_inner(word) {
    res = []
    elems = [...document.getElementsByTagName('a')];
    elems.forEach((elem) => { 
        if(elem.outerHTML.includes(word)) {
            res.push(elem)
        }
    })
    return(res)
}

用法：

用户“T3rm1”在本页提及多少次？

get_elements_by_inner("T3rm1").length

1

jQuery 被提及多少次？

get_elements_by_inner("jQuery").length

3

获取所有包含“控制论”一词的元素：

get_elements_by_inner("Cybernetic")

Answer 8

你可以这样做，不确定是否推荐这样做，但它对我有用。

[... document.querySelectorAll('a')].filter(el => el.textContent.includes('sometext'));

Answer 9

document.querySelectorAll('a').forEach(function (item) {
    if (item.innerText == 'SearchingText') {
        console.dir(item);
    }
});

Answer 10

I found the use of the newer syntax a little bit shorter compared to the others answer. So here's my proposal:

const callback = element => element.innerHTML == 'My research'

const elements = Array.from(document.getElementsByTagName('a'))
// [a, a, a, ...]

const result = elements.filter(callback)

console.log(result)
// [a]

JSfiddle.net

Answer 11

您可以使用 aTreeWalker来遍历 DOM 节点，找到包含该文本的所有文本节点，并返回它们的父节点：

const findNodeByContent = (text, root = document.body) => {
  const treeWalker = document.createTreeWalker(root, NodeFilter.SHOW_TEXT);

  const nodeList = [];

  while (treeWalker.nextNode()) {
    const node = treeWalker.currentNode;

    if (node.nodeType === Node.TEXT_NODE && node.textContent.includes(text)) {
      nodeList.push(node.parentNode);
    }
  };

  return nodeList;
}

const result = findNodeByContent('SearchingText');

console.log(result);

<a ...>SearchingText</a>

Answer 12

如果需要，从在 <=IE11 中工作的user1106925获取过滤器方法

您可以将扩展运算符替换为：

[].slice.call(document.querySelectorAll("a"))

和包括调用 a.textContent.match("your search term")

它工作得非常整洁：

[].slice.call(document.querySelectorAll("a"))
   .filter(a => a.textContent.match("your search term"))
   .forEach(a => console.log(a.textContent))