我有一个复杂的对象,如:
public class BusinessUnit
{
public TradingDesk TradingDesk { get; }
public string Division { get; }
public BusinessUnit(string division, TradingDesk tradingDesk)
{
Division = division;
TradingDesk = tradingDesk;
}
}
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我想将其映射到平面类型:
public class Row
{
//TradingDesk properties
public string TraderFirstName { get; set; }
public string TraderLastName { get; set; }
public string TradingDeskName { get; set; }
public string Division { get; set; }
}
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我已经配置AutoMapper
为TradingDesk
:
CreateMap<TradingDesk, Row>().ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.Name));
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所以以下测试通过:
[Test]
public void Should_Map_TradingDesk_To_Row()
{
var tradingDesk = Fixture.Create<TradingDesk>();
var mapped = AutoMapper.Map<Row>(tradingDesk);
mapped.TradingDeskName.Should()
.Be(tradingDesk.Name);
mapped.TraderFirstName.Should()
.Be(tradingDesk.Trader.FirstName);
mapped.TraderLastName.Should()
.Be(tradingDesk.Trader.LastName);
}
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但是,当我尝试映射BusinessUnit
到Row
我必须重新配置AutoMapper
为TradingDesk
这样:
CreateMap<BusinessUnit, Row>()
.ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.TradingDesk.Name))
.ForMember(vm => vm.TraderFirstName, op => op.MapFrom(src => src.TradingDesk.Trader.FirstName))
.ForMember(vm => vm.TraderLastName, op => op.MapFrom(src => src.TradingDesk.Trader.LastName));
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我想到的是AutoMapper
,当它需要映射应使用已配置的源和目标类型映射TradingDesk
到Row
同时映射BusinessUnit
.这样,我可以构建从最小到最大类型的配置,同时展平复杂对象,而无需为展平类型中的每个单独成员定义映射.
实际语法可能有所不同,因为我以静态方式使用 AutoMapper,但原理保持不变:
Mapper.CreateMap<BusinessUnit, Row>()
.ConvertUsing(source => Mapper.Map<TradingDesk, Row>(source.TradingDesk));
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