如何在我的 SupportFragment 中添加 YouTube 播放器？

Question

我的 XML 代码：

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    style="@style/Container.MainBackground"
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <fragment android:name="com.google.android.youtube.player.YouTubePlayerSupportFragment"
        android:layout_alignParentTop="true"
        android:id="@+id/youtube_view"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"/>
</RelativeLayout>

片段中的代码

public class VideoFragment extends YouTubePlayerSupportFragment implements YouTubePlayer.OnInitializedListener {

    static private final String DEVELOPER_KEY = "MyKey";
    static private final String VIDEO = "ToMpzhdUD1Q";
    static private final String VIDEO1 = "K77avo920Jc";
    @Nullable
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        View videoView = inflater.inflate(R.layout.video_fragment, container, false);
        getActivity().setTitle("Youtube");

        YouTubePlayerSupportFragment youTubePlayerSupportFragment = new YouTubePlayerSupportFragment();
        youTubePlayerSupportFragment.initialize(DEVELOPER_KEY, this);

        return videoView;
    }

    @Override
    public void onInitializationSuccess(YouTubePlayer.Provider provider, YouTubePlayer youTubePlayer, boolean b) {

        List<String> list = new ArrayList<>();
        list.add(VIDEO);
        list.add(VIDEO1);
        youTubePlayer.setPlayerStyle(YouTubePlayer.PlayerStyle.DEFAULT);
        youTubePlayer.cueVideos(list);

    }

    @Override
    public void onInitializationFailure(YouTubePlayer.Provider provider, YouTubeInitializationResult youTubeInitializationResult) {

        Toast.makeText(getContext(), "FAIL!" + youTubeInitializationResult.toString(), Toast.LENGTH_LONG)
                .show();

    }
}

在主要活动中：

getSupportFragmentManager().beginTransaction().replace(R.id.main_container,fragment).addToBackStack(null).commit();

尝试在 Drawer 中打开 Fragment 时出错：

java.lang.NullPointerException：尝试在 com.google.android.youtube.player.YouTubePlayerSupportFragment.onStart(Unknown来源）

Answer 1

这里的问题是您覆盖了超类YouTubePlayerSupportFragment中的onCreateView()方法，该方法不是抽象的，并且实际上有一个实现，如下所示：

    public View onCreateView(LayoutInflater var1, ViewGroup var2, Bundle var3) {
        this.c = new YouTubePlayerView(this.getActivity(), (AttributeSet)null, 0, this.a);
        this.a();
        return this.c;
    }

实际的变量名称和类型超出了本答案的范围。这里重要的是YouTubePlayerView在这里被实例化，并且您覆盖了该方法，因此在onStart()方法（也可以在YouTubePlayerSupportFragment中找到）中调用时YouTubePlayerView为 null 。

    public void onStart() {
        super.onStart();
        this.c.a();
    }

因此，基本上，您唯一需要的就是实例化您的VideoFragment类，并且，如果您想要实际的视频，而不是黑盒，则需要在创建片段时对其进行初始化（如下所示： ）

    public VideoFragment()
    {
        this.initialize("yourAPIKeyHere", this);
    }