Express 4 - 用promise.then链接res.json不起作用

Cha*_*kar 3 node.js promise express sequelize.js bluebird

我正在开发一个使用mysqlsequelize打包的快速4应用程序.Sequelize ORM使用promises从数据库中获取数据.我正在尝试在路由器中获取数据并发送json响应.当我试图链接then承诺的回调时,res.json我在控制台说出错Unhandled rejection TypeError: Cannot read property 'get' of undefined

// This works
employeeRouter.get("/:id", function(req, res){
   Employee.findById(req.params.id).then(function(data){
      res.json(data);
   });
});

// Replacing above code with following doesn't work
employeeRouter.get("/:id", function(req, res){
   Employee.findById(req.params.id).then(res.json);
});
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错误堆栈:

Unhandled rejection TypeError: Cannot read property 'get' of undefined
    at json (D:\Workstation\DataPro\CountryStats\node_modules\express\lib\response.js:241:21)
    at tryCatcher (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\util.js:16:23)
    at Promise._settlePromiseFromHandler (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\promise.js:504:31)
    at Promise._settlePromise (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\promise.js:561:18)
    at Promise._settlePromise0 (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\promise.js:606:10)
    at Promise._settlePromises (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\promise.js:685:18)
    at Async._drainQueue (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\async.js:138:16)
    at Async._drainQueues (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\async.js:148:10)
    at Immediate.Async.drainQueues [as _onImmediate] (D:\Workstation\DataPro\CountryStats\node_modules\bluebird\js\release\async.js:17:14)
    at processImmediate [as _immediateCallback] (timers.js:383:17)
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车型/ employee.js

var Sequelize = require('sequelize'),
    sequelize = require('../db-connect/sequelize');

(function(){

  // Use Strict Linting
  'use strict';

  // Define Sequalize
  var Employee = sequelize.define('employee', {
    empNo: { field: 'emp_no', type: Sequelize.INTEGER, primaryKey: true, autoIncrement: true },
    birthDate: { field: 'birth_date', type: Sequelize.DATE },
    firstName: { field: 'first_name', type: Sequelize.STRING },
    lastName: { field: 'last_name', type: Sequelize.STRING },
    gender: { field: 'gender', type: Sequelize.ENUM('M', 'F') },
    hireDate: { field: 'hire_date', type: Sequelize.DATE },
  });

  // Export
  module.exports = Employee;

}());
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DB-连接/ sequelize.js

var Sequelize = require('sequelize');

(function(){

  // Use Strict Linting
  'use strict';

  // Sequalize Connection
  var sequelize = null;

  // Create Sequalize Connection
  if(!sequelize){
    sequelize = new Sequelize('employees', 'root', '', {
      host: 'localhost',
      dialect: 'mysql',
      define: {
        timestamps: false
      }
    });
  }

  module.exports = sequelize;

}());
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路线/ employees.js

var express = require('express'),
    Employee = require('../models/employee');

(function(app){

  // Use Strict Linting
  'use strict';

  // Create Router
  var employeeRouter = express.Router();

  // Home Page
  employeeRouter.get("/", function(req, res){
    res.json({employees: ['all']});
  });

  // Get Specific Employee
  employeeRouter.get("/:id", function(req, res, next){
    Employee.findById(req.params.id).then(function(data){
      res.json(data);
    });
  });

  // ----------------------------------
  // Export
  // ----------------------------------

  module.exports = employeeRouter;

}());
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jfr*_*d00 15

当您res.json作为函数传递时,res对象会丢失,因此在json()执行时,它没有对象,并且您得到了您看到的错误.您可以使用.bind()以下方法解决此问题

employeeRouter.get("/:id", function(req, res){
   Employee.findById(req.params.id).then(res.json.bind(res));
});
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这将确保在res执行方法时对象保留在您的方法中.使用.bind()如上所述基本相同:

employeeRouter.get("/:id", function(req, res){
   Employee.findById(req.params.id).then(function(data) {
       return res.json(data);
   });
});
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实际上,.bind()实际上创建了一个存根函数,就像上面例子中的匿名函数一样.它只是为你而不是让你这样做.


再举一个例子,假设您有两个单独的res对象,res1并且res2来自两个单独的请求.

var x = res1.json;
var y = res2.json;

console.log(x === y);    // true, no association with either res1 or res2 any more
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这是因为引用res1.json只是获取对.json方法的引用.它用于res1获取该方法(从res1原型中获取,但是它具有方法,它只是指向该方法的指针,并且不再与包含该方法的对象关联.因此,当您传递res.json给一个函数,你没有附件res.然后当你传递res.json给它的函数去实际调用你的函数时,它会像这样调用它:

var z = res.json;
z();
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并且,当z()被调用时,this内部的值json最终成为undefined并且没有与res对象的连接.使用.bind()创建一个存根函数来调用它res.json(...)以保持与对象的连接,并确保this在执行方法时正确设置.