检查关系是否存在并返回真或假

Ale*_*lex 4 sql join relational-database

我有 3 个表,Category StepCategoryStepCategoryStep将另外两个表关联在一起。我想CategoryStep根据 StepID返回带有真/假列的所有类别,无论该关系是否存在。

表的架构很简单,

Category:
CategoryID      | CategoryName

Step:
StepID          | StepName

CategoryStep:
CategoryStepID  | CategoryID    | StepID
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尝试根据 StepID 获取结果时,我只获取存在的关系,而不获取不存在的关系。

SELECT [CategoryID], [Category], CAST(CASE WHEN [CategoryStep].[CategoryStep] IS NULL THEN 0 ELSE 1 END AS BIT) AS related
FROM Category
LEFT JOIN CategoryStep ON Category.CategoryID = CategoryStep.CategoryID
INNER JOIN Step ON CategoryStep.StepID = Step.StepID
WHERE Step.StepID = 2
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步骤表:

|StepID | StepName
|-------|---------
| 1     | StepOne
| 2     | StepTwo
| 3     | StepThree
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分类表:

| CategoryID | CategoryName
|------------|-------------
| 1          | Holidays
| 2          | States
| 3          | Cities
| 4          | Animals
| 5          | Food
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类别步骤表

| CategoryStepID | CategoryID | StepID
|----------------|------------|-------
| 1              | 1          | 1
| 2              | 1          | 2     <--
| 3              | 2          | 1
| 4              | 2          | 3
| 5              | 3          | 2     <--
| 6              | 4          | 1
| 7              | 4          | 2     <--
| 8              | 4          | 3
| 9              | 5          | 1
| 10             | 5          | 3
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因此,如果我正在寻找 StepID = 2,我正在寻找的结果表是:

| CategoryID | Category | Related
|------------|----------|--------
| 1          | Holidays | 1
| 2          | States   | 0
| 3          | Cities   | 1
| 4          | Animals  | 1
| 5          | Food     | 0
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Tim*_*sen 5

尝试将 替换INNER JOINLEFT JOIN

更新:

您最初尝试的致命缺陷是WHERE条款。您正在执行正确的LEFT JOIN,但该WHERE子句正在过滤掉不匹配的类别记录。在下面的查询中,我将步骤 ID 的检查移到了它所属的连接条件中。

SELECT [CategoryID], [Category],
    CAST(CASE WHEN [CategoryStep].[CategoryStep] IS NULL THEN 0 ELSE 1 END AS BIT) AS related
FROM Category
LEFT JOIN CategoryStep
    ON Category.CategoryID = CategoryStep.CategoryID AND
       CategoryStep.StepCodeID = 2
LEFT JOIN Step
    ON CategoryStep.StepID = Step.StepID
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