Ale*_*lex 4 sql join relational-database
我有 3 个表,Category Step和CategoryStep,CategoryStep将另外两个表关联在一起。我想CategoryStep根据 StepID返回带有真/假列的所有类别,无论该关系是否存在。
表的架构很简单,
Category:
CategoryID | CategoryName
Step:
StepID | StepName
CategoryStep:
CategoryStepID | CategoryID | StepID
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尝试根据 StepID 获取结果时,我只获取存在的关系,而不获取不存在的关系。
SELECT [CategoryID], [Category], CAST(CASE WHEN [CategoryStep].[CategoryStep] IS NULL THEN 0 ELSE 1 END AS BIT) AS related
FROM Category
LEFT JOIN CategoryStep ON Category.CategoryID = CategoryStep.CategoryID
INNER JOIN Step ON CategoryStep.StepID = Step.StepID
WHERE Step.StepID = 2
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步骤表:
|StepID | StepName
|-------|---------
| 1 | StepOne
| 2 | StepTwo
| 3 | StepThree
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分类表:
| CategoryID | CategoryName
|------------|-------------
| 1 | Holidays
| 2 | States
| 3 | Cities
| 4 | Animals
| 5 | Food
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类别步骤表
| CategoryStepID | CategoryID | StepID
|----------------|------------|-------
| 1 | 1 | 1
| 2 | 1 | 2 <--
| 3 | 2 | 1
| 4 | 2 | 3
| 5 | 3 | 2 <--
| 6 | 4 | 1
| 7 | 4 | 2 <--
| 8 | 4 | 3
| 9 | 5 | 1
| 10 | 5 | 3
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因此,如果我正在寻找 StepID = 2,我正在寻找的结果表是:
| CategoryID | Category | Related
|------------|----------|--------
| 1 | Holidays | 1
| 2 | States | 0
| 3 | Cities | 1
| 4 | Animals | 1
| 5 | Food | 0
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尝试将 替换INNER JOIN为LEFT JOIN。
更新:
您最初尝试的致命缺陷是WHERE条款。您正在执行正确的LEFT JOIN,但该WHERE子句正在过滤掉不匹配的类别记录。在下面的查询中,我将步骤 ID 的检查移到了它所属的连接条件中。
SELECT [CategoryID], [Category],
CAST(CASE WHEN [CategoryStep].[CategoryStep] IS NULL THEN 0 ELSE 1 END AS BIT) AS related
FROM Category
LEFT JOIN CategoryStep
ON Category.CategoryID = CategoryStep.CategoryID AND
CategoryStep.StepCodeID = 2
LEFT JOIN Step
ON CategoryStep.StepID = Step.StepID
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