Nic*_*unt 4 html xslt foreach transform
我试图将一些表示图像库的xml转换为html表.(必须使用html而不是css). 如何</tr><tr>使用xsl每隔六个左右添加行中断?
我有这个:
<xsl:for-each select="//email/gallery" >
<td>
<img>
<xsl:attribute name="src">
<xsl:value-of select="gallery-image-location"/>
</xsl:attribute>
<xsl:attribute name="alt">
<xsl:value-of select="gallery-image-alt"/>
</xsl:attribute>
</img>
</td>
<xsl:if test="????">
</tr>
<tr>
</xsl:if>
<xsl:for-each>
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在Javascript中我会做类似的事情:
for (i=0; i<gallery.length; i++) {
htm += '<td><img src="' +
gallery[i].gallery-image-location +
'" alt="'+ gallery[i].gallery-image-alt +'"></td>';
if (i%6 == 5 && i != gallery.length-1) {
htm += '</tr><tr>';
}
}
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如何使用xsl每隔六个左右添加行中断?
在XSLT中你没有!
XSLT处理节点,而不是标签.
这是XSLT的位置分组方式:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="gallery[position() mod 6 = 1]">
<tr>
<xsl:apply-templates mode="proc"
select=".|following-sibling::gallery[not(position() > 5)]"
/>
</tr>
</xsl:template>
<xsl:template match="gallery" mode="proc">
<td>
<img src="{gallery-image-location}" alt="{gallery-image-alt}"/>
</td>
</xsl:template>
<xsl:template match="gallery[not(position() mod 6 = 1)]"/>
</xsl:stylesheet>
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当此转换应用于以下XML文档时:
<email>
<gallery>
<gallery-image-location>http://server/picts/1</gallery-image-location>
<gallery-image-alt>Description 1</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/2</gallery-image-location>
<gallery-image-alt>Description 2</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/3</gallery-image-location>
<gallery-image-alt>Description 3</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/41</gallery-image-location>
<gallery-image-alt>Description 4</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/5</gallery-image-location>
<gallery-image-alt>Description 5</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/6</gallery-image-location>
<gallery-image-alt>Description 6</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/7</gallery-image-location>
<gallery-image-alt>Description 7</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/8</gallery-image-location>
<gallery-image-alt>Description 8</gallery-image-alt>
</gallery>
<gallery>
<gallery-image-location>http://server/picts/9</gallery-image-location>
<gallery-image-alt>Description 9</gallery-image-alt>
</gallery>
</email>
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产生了想要的正确结果:
<tr>
<td>
<img src="http://server/picts/1" alt="Description 1"/>
</td>
<td>
<img src="http://server/picts/2" alt="Description 2"/>
</td>
<td>
<img src="http://server/picts/3" alt="Description 3"/>
</td>
<td>
<img src="http://server/picts/41" alt="Description 4"/>
</td>
<td>
<img src="http://server/picts/5" alt="Description 5"/>
</td>
<td>
<img src="http://server/picts/6" alt="Description 6"/>
</td>
</tr>
<tr>
<td>
<img src="http://server/picts/7" alt="Description 7"/>
</td>
<td>
<img src="http://server/picts/8" alt="Description 8"/>
</td>
<td>
<img src="http://server/picts/9" alt="Description 9"/>
</td>
</tr>
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如果您使用的是XSLT 2
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="email">
<xsl:for-each-group select="gallery" group-by="(position() - 1) idiv 6">
<tr>
<xsl:apply-templates select="current-group()"/>
</tr>
</xsl:for-each-group>
</xsl:template>
<xsl:template match="gallery">
<td>
<img src="{gallery-image-location}" alt="{gallery-image-alt}"/>
</td>
</xsl:template>
</xsl:stylesheet>
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