XAM*_*cky 5 serialization json rust serde
扩展我之前的问题,你如何处理包含混合的数组structs?我试过看serde_json::Value源头.但是它没有处理两种不同的情况structs.
我不能简单地合并它们,并且在它们的属性上使用Options,因为这会使单个struct变得难以处理,并且它们必须是不同的.
#[derive(Clone, Debug, Deserialize)]
struct WebResponse {
foo: Vec<Structs>,
}
enum Structs {
Foo(Foo),
Bar(Bar),
}
#[derive(Clone, Debug, Deserialize)]
struct Foo {
name: String,
baz: Vec<String>,
}
#[derive(Clone, Debug, Deserialize)]
struct Bar {
quux: u64
}
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{
"foo": [
{
"name": "John",
"baz": ["Lorem", "Ipsum"]
},
{
"quux": 17
}
]
}
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有几种方法可以解决这个问题.如果你有几个变种,最简单的方法是简单地Deserialize手动实现,如下所示:
impl serde::de::Deserialize for Structs {
fn deserialize<D>(deserializer: &mut D) -> Result<Self, D::Error>
where D: serde::Deserializer,
{
deserializer.deserialize(Visitor)
}
}
struct Visitor;
impl serde::de::Visitor for Visitor {
type Value = Structs;
fn visit_map<V>(&mut self, mut visitor: V) -> Result<Structs, V::Error>
where V: serde::de::MapVisitor,
{
let s: String = try!(visitor.visit_key()).expect("got struct with no fields");
let val = match &s as &str {
"name" => {
Ok(Structs::Foo(Foo {
name: try!(visitor.visit_value()),
baz: {
let s: String = try!(visitor.visit_key()).expect("baz field");
assert_eq!(&s, "baz");
try!(visitor.visit_value())
},
}))
},
"baz" => {
Ok(Structs::Foo(Foo {
baz: try!(visitor.visit_value()),
name: {
let s: String = try!(visitor.visit_key()).expect("name field");
assert_eq!(&s, "name");
try!(visitor.visit_value())
},
}))
},
"quux" => {
Ok(Structs::Bar(Bar {
quux: try!(visitor.visit_value())
}))
},
other => panic!("no struct has field `{}`", other),
};
try!(visitor.end());
val
}
}
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这种实现的问题在于它显然不能扩展.你可以做的是创建一个新的Deserializer,你给出第一个找到的字段名称,并覆盖deserialize_map通过自定义处理各种结构的方法MapVisitor.
如果您认为这是其他序列化框架支持的常见情况,请随时在serde存储库或serde-json存储库上发布错误报告.我确信有一种方法可以自动生成这样的实现,但这肯定不是微不足道的.
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