PHP 将 DateInterval 转换为 int

Question

我正在使用此代码：

$due_date = new DateTime($_POST['due_date']);

$today = new DateTime();
$months = $due_date->diff($today);

$months->format("%m");

$fine = 0.02 * $price * $months; // i got error in this line

$bill = $price + $fine;

我想计算一下，如果有人迟交，那么他们每个月都会被罚款。错误信息是：

Object of class DateInterval could not be converted to int

Answer 1

出现错误消息$months是因为不是 int，而是像这样的 Datetime 对象：

DateInterval Object
(
    [y] => 0
    [m] => 4
    [d] => 12
    [h] => 6
    [i] => 56
    [s] => 9
    [weekday] => 0
    [weekday_behavior] => 0
    [first_last_day_of] => 0
    [invert] => 0
    [days] => 133
    [special_type] => 0
    [special_amount] => 0
    [have_weekday_relative] => 0
    [have_special_relative] => 0
)

您可以像这样获得月份的整数值

$due_date = new DateTime('13-02-2016');

$today = new DateTime();
$months = $due_date->diff($today);

echo $months->m;

在PHP Sandbox 中检查以上结果

所以基本上你的代码看起来像

$due_date = new DateTime($_POST['due_date']);

$today = new DateTime();
$months = $due_date->diff($today);

$fine = 0.02 * $price * $months->m; // i got no error in this line

$bill = $price + $fine;