我试图在不同节点上获取许多不同长度的列表,将它们收集在一个节点中,然后让主节点将它们放在一组中。该列表rout_array在每个节点中命名。请注意,中的元素rout_array只是整数,并且跨节点不唯一。
Traceback (most recent call last):
File "prout.py", line 160, in <module>
main()
File "prout.py", line 153, in main
num = DetermineRoutingNumber(steps, goal, vertexSetSize)
File "prout.py", line 129, in DetermineRoutingNumber
comm.Gather(send_buffer, recv_buffer, root = 0)
File "MPI\Comm.pyx", line 589, in mpi4py.MPI.Comm.Gather (c:\projects\mpi4py\src\mpi4py.MPI.c:97806)
File "MPI\msgbuffer.pxi", line 525, in mpi4py.MPI._p_msg_cco.for_gather (c:\projects\mpi4py\src\mpi4py.MPI.c:34678)
File "MPI\msgbuffer.pxi", line 446, in mpi4py.MPI._p_msg_cco.for_cco_send (c:\projects\mpi4py\src\mpi4py.MPI.c:33938)
File "MPI\msgbuffer.pxi", line 148, in mpi4py.MPI.message_simple (c:\projects\mpi4py\src\mpi4py.MPI.c:30349)
File "MPI\msgbuffer.pxi", line 93, in mpi4py.MPI.message_basic (c:\projects\mpi4py\src\mpi4py.MPI.c:29448)
KeyError: 'O'
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我不知道'O'当我的代码中没有字符串时我是如何得到 KeyError 的。所有列表都包含整数,numpy 数组包含整数,这里唯一活动的字典只有键的整数。需要注意的是,每个节点都会输出这个错误。
import numpy, math
from mpi4py import MPI
from sympy.combinatorics import Permutation as Perm
def GetEdges(size,file):
"""This function takes in a file of edges in a graph in the form 'u,v'
without quotes, where u and v are vertices of the graph. It then
generates a permutation that swaps those vertices, and returns these
transpositions."""
edgeFile = open(file, "r")
edges = []
for line in edgeFile:
line = line.strip()
line = line.split(",")
for vertex in line:
line[line.index(vertex)] = int(vertex)
edges.append(Perm([line], size = size))
edgeFile.close()
edges.append(Perm([[size - 1]], size = size))
return edges
def AreDisjoint(p1,p2):
"""This function determines whether or not two permutations move any
common elements, and returns the appropriate boolean."""
v1 = set(p1.support())
v2 = set(p2.support())
return len(v1 & v2) == 0
def GetMatchings(edges, maxMatching, size):
"""This function takes in a set of edges given by GetEdges(), and
generates all possible matchings in the given graph. It then converts
each matching into its rank given by lexicographical order, and appends
that rank to a set, which is then returned."""
stepDict = {1:set(edges)}
steps = set(edges)
for i in range(1,maxMatching):
temp = set()
for p1 in stepDict[1]:
for p2 in stepDict[i]:
newPerm = p1 * p2
if AreDisjoint(p1,p2) and newPerm not in steps:
temp.add(newPerm)
steps.add(newPerm)
stepDict[i+1] = temp
newSteps = set()
for step in steps:
newSteps.add(step.rank())
return newSteps
def FromRank(rank,level):
"""This function takes in a rank and size of a permutation, then returns
the permutation that lies at the rank according to lexicographical
ordering. """
lst = list(range(level + 1))
perm = []
while lst:
fact = math.factorial(len(lst) - 1)
index, rank = divmod(rank, fact)
perm.append(lst.pop(index))
assert rank == 0
return perm
def SplitArrayBetweenNodes(rank, rem, length):
"""This function takes in the rank of a node and any remainder after
dividing up an array between all the nodes. It then returns a starting
and ending partition index unique to each node."""
if rem != 0:
if rank in list(range(rem)):
if rank == 0:
part_start = 0
part_end = length
else:
part_start = rank * (length + 1)
part_end = part_start + length
else:
part_start = rank * length + rem
part_end = part_start + length - 1
else:
part_start = rank * length
part_end = part_start + length - 1
return part_start, part_end
def DetermineRoutingNumber(steps, goal, vertexSetSize):
"""This function takes in the matchings created by GetMatchings(),
and calculates all possible products between its own elements. It then
takes all unique products, and calculates all possible prducts between
the matching set and the previous output. This repeats until all
permutations of a given type are found. The level at which this occurs
is then returned."""
comm = MPI.COMM_WORLD
rank = comm.Get_rank()
size = comm.Get_size()
length = len(steps)
rem = length % size
part_len = length // size
part_start, part_end = SplitArrayBetweenNodes(rank,rem, part_len)
permDict = {1: steps}
i = 1
while True:
rout_array = set()
work_array = set(list(permDict[i])[part_start:part_end + 1])
#Calculate all possible products
for p1 in permDict[1]:
for p2 in work_array:
p2_perm = Perm(FromRank(p2,vertexSetSize - 1))
p1_perm = Perm(FromRank(p1,vertexSetSize - 1))
new = p2_perm * p1_perm
if new(0) == 0 or new(0) == 1:
order = new.rank()
rout_array.add(order)
#All nodes send their work to master node
comm.Barrier()
send_buffer = numpy.array(rout_array)
sendcounts = numpy.array(comm.gather(len(rout_array), root = 0))
if rank == 0:
recv_buffer = numpy.empty(sum(sendcounts), dtype = int)
else:
recv_buffer = None
comm.Gatherv(sendbuf = send_buffer, recvbuf = (recv_buffer, sendcounts), root = 0)
#Generate input for next level of the loop, and weed out repeats.
permDict[i+1] = rout_array
for j in range(1,i+1):
permDict[i+1] = permDict[i+1] - permDict[j]
def main():
file = "EdgesQ2.txt"
maxMatching = 2
vertexSetSize = 4
edges = GetEdges(vertexSetSize, file)
steps = GetMatchings(edges, maxMatching, vertexSetSize)
goal = 2 * math.factorial(vertexSetSize-1)
num = DetermineRoutingNumber(steps, goal, vertexSetSize)
print(num)
main()
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请注意,maxMatching = 2和vertexSetSize = 4在这个例子。输出应该是3。
0,1
1,2
2,3
0,3
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请注意,maxMatching = 4和vertexSetSize = 8在这个例子。输出应该是4。
0,1
0,3
0,4
1,2
1,5
2,3
2,6
3,7
4,5
4,7
5,6
6,7
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如果不同进程的长度不同,则需要使用 vector variant Gatherv。使用该函数,您可以提供一个包含各种长度(recvcounts)的数组。
不幸的是,mpi4py 文档目前没有描述如何使用Gatherv或任何其他向量变体。这是一个简单的例子:
#!/usr/bin/env python3
import numpy as np
from mpi4py import MPI
import random
comm = MPI.COMM_WORLD
rank = comm.Get_rank()
root = 0
local_array = [rank] * random.randint(2, 5)
print("rank: {}, local_array: {}".format(rank, local_array))
sendbuf = np.array(local_array)
# Collect local array sizes using the high-level mpi4py gather
sendcounts = np.array(comm.gather(len(sendbuf), root))
if rank == root:
print("sendcounts: {}, total: {}".format(sendcounts, sum(sendcounts)))
recvbuf = np.empty(sum(sendcounts), dtype=int)
else:
recvbuf = None
comm.Gatherv(sendbuf=sendbuf, recvbuf=(recvbuf, sendcounts), root=root)
if rank == root:
print("Gathered array: {}".format(recvbuf))
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如您所见,mpi4py 不会将 sendcounts 或 recvcounts 作为额外参数,而是作为参数的元组/列表recvbuf。如果通过(recvbuf, sendcounts),它将从 recvbuf 派生类型。将进行位移/偏移,以便来自所有等级的数据连续存储并按等级排序。
基本上,mpi4py 会疯狂地猜测您对各种形式的recvbuf参数可能意味着什么。完整且明确的形式是(buffer, counts, displacements, type)。
KeyError:相当容易混淆的名称rout_array是 a set,它不是 的有效输入numpy.array。Aset既不是序列也没有数组接口。不幸的是,不是失败,而是numpy.array创建了一个ndarray没有维度的非常奇怪的对象。您可以将数组创建包装在列表中:
send_buffer = numpy.array(list(rout_array))
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集体有效,但循环不会终止,考虑到 中没有return或break在while true循环中,这并不奇怪DetermineRoutingNumber。