Ale*_*lov 5 django django-templates django-forms django-views django-crispy-forms
我有一个登录表单,我想在标题中放入模式窗口。
Urls.py
url(r'^account/login/$', appuser_views.LoginView.as_view(template_name = 'account/login/index.html', form_class = appuser_forms.LoginForm, target_url = LOGIN_TARGET_URL)),
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views.py
class LoginView(ResendEmailToUsersMixin, AjaxFormView):
def process_form(self, request, form):
data = form.cleaned_data
a = AppUserCredential.objects.select_related('appuser').filter(
data1 = data['email_address'],
credential_type = AppUserCredential.CREDENTIAL_TYPES.EMAIL_PASSWORD,
appuser__status = AppUser.STATUS_TYPES.Active
).first()
force_error = False
if a is None:
response = self.resend_email_to_users(data = data)
if response is not None:
return response
#If no email exists force the error and don't check the password
force_error = True
if force_error or not a.check_password(data['password']):
return AjaxErrorResponse(code="login_error", title="Username or Password Error", message="The username or password you have provided don’t match our records. Please check your entries and try again.")
a.appuser.login(request)
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表格
class LoginForm(AjaxForm):
email_address = forms.EmailField(label = "Email Address", required = True, max_length = 100,
widget = forms.TextInput(attrs = {'placeholder': 'email@domain.com', 'autocomplete':'off'}))
password = forms.CharField(label = "Password", required = True, max_length = 100,
widget = forms.PasswordInput(attrs = {'placeholder': 'Password', 'autocomplete':'off'}))
def setup_form_helper(self, helper):
helper.form_id = 'login_form'
helper.layout = Layout(
'email_address',
'password',
Div(
Submit('submit', 'Login', css_class='btn btn-primary'),
css_class="form-group text-center"
),
HTML('<p class="pull-right light-top-bottom-padding"><a href="/account/forgot-password" title="Forgot Password">Forgot Password?</a></p>')
)
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/templates/account/login/index.html
...
{% crispy form form.helper %}
...
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/templates/layouts/header.html
如何在模态窗口中放置{% crispy form form.helper %}模态窗口?谢谢。
UPD1:
如果我{% crispy form form.helper %}输入header.html,则会收到错误消息
在u'[{\'False \':False,\'None \':None,\'True \':True},中对键[form]的查找失败/ VariableDoesNotExist存在/
UPD2: 模态形式:
<a href="javascript:void(0);" class="text-btn" data-toggle="modal" data-target="#login">login</a>
<div id="login" class="modal fade" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Modal Header</h4>
</div>
<div class="modal-body">
<p>Some text in the modal.</p>
<div class="panel-body">
<header class="section-title text-center normal-top-bottom-padding">
<h1>Login</h1>
</header>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
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登录链接应该在每个页面中。
如果您想在所有页面中显示表单,则需要将form(最好调用它login_form,这样它不会与您可能拥有的其他表单冲突)添加到每个视图的上下文中。
为了避免在所有视图中重复执行此操作,Django 有上下文处理器。您将它们包含在settings.py的TEMPLATES变量中。例子
TEMPLATES = [{
...
'OPTIONS': {
'context_processors': [
...
'myapp.context_processors.add_my_login_form',
],
}]
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然后,创建一个名为 的文件并在其中context_processors.py添加该函数。add_my_login_form()该函数返回login_form所有请求的请求上下文。
def add_my_login_form(request):
return {
'login_form': LoginForm(),
}
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由于您要在每个页面中呈现表单,因此最好使用模板缓存。
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