Codeigniter-选择不在其中的ID（另一个查询结果）

Question

我正在研究酒店预订系统，目前我正在尝试选择可用的房间（未预订）。

Rooms DB Structure:
ID
ROOM NAME
CAPACITY

HOTEL RESERVATIONS DB STRUCTURE:
ID
CHECK_IN
CHECK_OUT
ROOMS
...

这是我当前的代码：

function searchFreeRooms($data){
  $check_in = $data['fields']['check_in'];
  $check_out = $data['fields']['check_out'];
  $this->db->select("*");
  $this->db->from('core_hotel_rooms');
  $this->db->where("id NOT IN (select rooms,total_guests from res_hotel where check_in <= '$check_in' AND check_out >= '$check_in' OR check_in <= '$check_out' AND check_out >= '$check_out' OR check_in >= '$check_in' AND check_out <= '$check_out' ) ");
  $query = $this->db->get();
  return $query->result();
 }

用户可以一次预订许多房间，并且保留的房间ID存储在“ ROOMS”列中，并用逗号分隔，例如：2，3，5

在我前面，不应显示此列中存在的房间，但是我遇到了麻烦，因为仅选择了逗号前的第一个id（房间），例如：2,3,5>仅选择了2，而仍然选择了3,5显示在我的前面。

问题在这里： $this->db->where("id NOT IN (select rooms,total_guests from res_hotel where check_in <= '$check_in' AND check_out >= '$check_in' OR check_in <= '$check_out' AND check_out >= '$check_out' OR check_in >= '$check_in' AND check_out <= '$check_out' ) ");

我尝试了此方法：$this->db->where("id NOT IN (1, 2) ");它完美地工作，但第二查询没有上层方法。

对不起我的英语不好...

非常感谢所有能提供帮助的人！

Answer 1

考虑使用括号

   $this->db->where("id NOT IN (select rooms,total_guests from res_hotel where (check_in <= '$check_in' AND check_out >= '$check_in') OR (check_in <= '$check_out' AND check_out >= '$check_out') OR (check_in >= '$check_in' AND check_out <= '$check_out' ) ) ");

Answer 2

最后，在您的所有帮助下，我解决了我的问题！

工作代码：

function searchFreeRooms($data){
  $check_in = $data['fields']['check_in'];
  $check_out = $data['fields']['check_out'];
  $query1 = $this->db->query("select rooms from res_hotel where (check_in <= '$check_in' AND check_out >= '$check_in') OR (check_in <= '$check_out' AND check_out >= '$check_out') OR (check_in >= '$check_in' AND check_out <= '$check_out' )");
  $query1_result = $query1->result();
  $room_id= array();
  foreach($query1_result as $row){
     $room_id[] = $row->rooms;
   }
  $room = implode(",",$room_id);
  $ids = explode(",", $room);
  $this->db->select("*");
  $this->db->from('core_hotel_rooms');
  $this->db->where_not_in('id', $ids);
  $query = $this->db->get();
  return $query->result();
 }

非常感谢！