Fra*_*ier 3 javascript arrays json
我有一个按不同类别分组的数组,每个类别都嵌套了更多具有不同值(数字和字符串)的对象,我必须减少它们(字符串除外).Reduce工作正常,数值为总和,但它会覆盖保留最后一个的字符串值.
我正在尝试按类别缩小对象/字典并使用每个类别的单位总和填充表格,但如果子类别和名称不同,则不要求它们.
这是一个演示:
var data = {
'Category xxxx': [
{
units: 1234,
subcategory: 'wolves',
name: 'Starks'
},
{
units: 1345354,
subcategory: 'wolves',
name: 'Starks'
},
{
units: 666,
subcategory: 'dragons',
name: 'Targaryens'
}
],
'Category yyyy': [
{
units: 7783,
subcategory: 'lions',
name: 'Lanisters'
},
{
units: 1267878,
subcategory: 'spires',
name: 'Martells'
}
]
}
var test = _.map(data, function (value, key) {
var returnedData = {
Category: key,
units: _(value).reduce(function (memo, metrics) {
return memo + metrics.units;
}, 0),
subcategory: _(value).reduce(function (memo, metrics) {
return metrics.subcategory;
}, 0),
name: _(value).reduce(function (memo, metrics) {
return metrics.name;
}, 0),
};
return returnedData;
});
console.log(test)Run Code Online (Sandbox Code Playgroud)
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单位(整数)加起来很好但字符串被最后一个迭代的字符串属性覆盖.
我想获得这样的东西,如果字符串不同,整数就不会加起来.
returnedData = {
'Category xxxx': [
{
units: 1346588,
chivalry: 'wolves',
name: 'Starks'
},
{
units: 666,
subcategory: 'dragons',
name: 'Targaryens'
}
],
'Category yyyy': [
{
clicks: 7783,
subcategory: 'lions',
name: 'Lanisters'
},
{
clicks: 1267878,
subcategory: 'spires',
name: 'Martells'
}
]
}
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最好的方法是什么?
最后,该提议使用对象作为对象项的引用result.
如果没有result可用的对象,则会创建一个具有所需类别的新对象.对于子类别,它会生成一个推送到结果数组的元素.
计数保持与hash参考元素result.
var data = { 'Category xxxx': [{ clicks: 1234, subcategory: 'dogs', name: 'jhon doe' }, { clicks: 1345354, subcategory: 'dogs', name: 'jhon doe' }], 'Category yyyy': [{ clicks: 7783, subcategory: 'frogs', name: 'lanisters' }, { clicks: 1267878, subcategory: 'rats', name: 'perry' }] },
result = {};
Object.keys(data).forEach(function (k) {
var hash = Object.create(null);
if (!result[k]) {
result[k] = [];
}
data[k].forEach(function (a) {
if (!hash[a.subcategory]) {
hash[a.subcategory] = { clicks: 0, subcategory: a.subcategory, name: a.name };
result[k].push(hash[a.subcategory]);
}
hash[a.subcategory].clicks += a.clicks;
});
});
console.log(result);Run Code Online (Sandbox Code Playgroud)