(Hibernate Oracle无法插入NULL)如何插入自动生成的ID？

Question

我正在使用hibernate执行CRUD操作的项目.我有用户模型,我试图插入信息,但不断收到此错误

Hibernate: insert into APPUSER (dob, email, firstName, lastName, password) values (?, ?, ?, ?, ?)
Jun 21, 2016 2:17:07 AM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 1400, SQLState: 23000
Jun 21, 2016 2:17:07 AM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: ORA-01400: cannot insert NULL into ("MYAPP8785"."APPUSER"."ID")

用户模型看起来像

@Entity
@Table(name="APPUSER")
public class AppUser {


    @Id 
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int id;

    @Email
    @Size(max = 50)
    private String email;

    @Column
    private String dob;

    @Column
    private String firstName;

    @Column
    private String lastName;

    @Column(name = "password", nullable = false)
    private String password;
}

像Hibernate这样的属性

properties.put("hibernate.dialect","org.hibernate.dialect.MySQLDialect");
//properties.put("hibernate.current_session_context_class","thread");
properties.put("hibernate.hbm2ddl.auto","update");
properties.put("hibernate.show_sql","true");

我的印象是hibernate会为我自动生成id并使用sequence插入它们

Answer 1

一些错误:

• 使用正确的方言:( org.hibernate.dialect.Oracle10gDialect没有11g的特定方言).
• 不要使用原始类型来生成hibernate生成的ID(使用Integer,不是int)

IDENTITY从版本12c开始,oracle仅支持ID生成

您应该使用其他策略,例如使用序列.

映射看起来像:

@Id
@SequenceGenerator(name = "generator", sequenceName = "ID_SEQUENCE", allocationSize = 1)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "generator")
@Column(name = "ID")
private Integer id;