尾随空格plsql

0 sql oracle trailing

我需要找到带尾随空格的记录.我尝试使用构建查询Length(rtrim),但它没有返回所需的记录.

例如

abc "
abc       "
abc                                                               "
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请协助

Use*_*r42 5

我认为你走在了正确的轨道上.以下示例将返回第二个和第三个文本,但不返回第一个文本.

SELECT * FROM
    (SELECT 'abc' AS text FROM DUAL
     UNION ALL
     SELECT 'abc       ' AS text FROM DUAL
     UNION ALL
     SELECT 'abc                        ' AS text FROM DUAL)
WHERE LENGTH(RTRIM(text)) != LENGTH(text);
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或者对于包含包含可能尾随空格的文本YOURTABLE的列的表YOURCOLUMN:

SELECT * FROM
YOURTABLE
WHERE LENGTH(RTRIM(YOURCOLUMN)) != LENGTH(YOURCOLUMN);
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如果你也有HORIZONTAL TAB,LINE FEED或者CARRIAGE RETURN您可以使用TRANSLATE函数来对待这些正常的空间:

SELECT * FROM
    (SELECT 'abc' AS text FROM DUAL
     UNION ALL
     SELECT 'abc' || CHR(09) AS text FROM DUAL
     UNION ALL
     SELECT 'abc' || CHR(10) AS text FROM DUAL
     UNION ALL
     SELECT 'abc' || CHR(13) AS text FROM DUAL
     UNION ALL
     SELECT 'abc           ' AS text FROM DUAL)
WHERE LENGTH(RTRIM(TRANSLATE(text, CHR(09) || CHR(10) || CHR(13), ' '))) != LENGTH(text);
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