rxjava中的异常处理

Question

我试图习惯rxjava,我试图QuoteReader在Observable中调用下面的内容.我不知道如何处理抛出的异常,

public class QuoteReader {
   public Map<String, Object> getQuote() throws IOException{
       OkHttpClient okHttpClient = new OkHttpClient();
       Request request = new Request.Builder().url("http://quotes.rest/qod.json").build();
       Gson gson = new Gson();
       Map<String, Object> responseMap = null;

       try(Response response = okHttpClient.newCall(request).execute()) {
         responseMap = gson.fromJson(response.body().string(), Map.class);
         System.out.println("response map : "+responseMap);
       } catch(IOException ioe) {
         ioe.printStackTrace();
         throw ioe;
       } finally {
         okHttpClient = null;
         request = null;
       }
    return responseMap;
  }
}

以下是我想写的rx代码,

rx.Observable.just(new QuoteReader().getQuote()) //compile time error saying unhandled exception
              .subscribe(System.out::println);

我应该如何更新代码来处理异常.谢谢!

Answer 1

使用fromCallable它允许你的方法抛出(另外,它会被懒惰地评估,而不是在你进入Observable世界之前):

rx.Observable.fromCallable(() -> new QuoteReader().getQuote())
          .subscribe(System.out::println, Throwable::printStackTrace);