Swa*_*bhu 3 arrays tuples ios swift
这是在tableview cellforrowatindexpath中
var valueArray:[(String,String)] = []
if !contains(valueArray, v: (title,status)) {
let v = (title,status)
valueArray.append(v)
}
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这是在didselectrowatIndexPath里面
let cell = self.tableView.cellForRowAtIndexPath(selectedRow!)
var newTuple = (cell!.textLabel!.text!, cell!.detailTextLabel!.text!)
let index = valueArray.indexOf(newTuple)
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但我没有得到索引.抛出错误无法将类型'(String,String)'的值转换为预期的参数类型'@noescape((String,String))throws - > Bool'.我在这里做错了什么?
Mar*_*n R 15
可以比较元组的相等性(从Swift 2.2/Xcode 7.3.1开始),但它们不符合Equatable协议.因此,您必须使用基于谓词的变体indexOf来定位数组中的元组.例:
let valueArray = [("a", "b"), ("c", "d")]
let tuple = ("c", "d")
if let index = valueArray.indexOf({ $0 == tuple }) {
print("found at index", index)
}
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在Swift 4中,该方法已重命名为firstIndex(where:):
if let index = valueArray.firstIndex(where: { $0 == tuple }) {
print("found at index", index)
}
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这是我查找元组索引的选项
var tuple: [(key: String, value: AnyObject)] = [("isSwap", true as AnyObject), ("price", 120 as AnyObject)]
if let index = tuple.index(where: {($0.key == "price")}) {
print(index)
}
//prints 1
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