Phpstorm有检查:Invocation parameter types are not compatible with declared.
我很惊讶php允许使用基类型作为子类型.
interface Base
{
public function getId();
}
interface Child extends Base
{
}
interface SecondChildType extends Base
{
}
class ChildImpl implements Child
{
public function getId()
{
return 1;
}
}
class SecondChildTypeImpl implements SecondChildType
{
public function getId()
{
return 2;
}
}
class BaseService
{
public function process(Base $base)
{
$childService = new ChildService($base);
return $childService->process($base); //Invocation parameter types are not compatible with declared
}
}
class ChildService
{
public function process(Child $child)
{
return $child->getId();
}
}
class InheritanceTest extends \PHPUnit_Framework_TestCase
{
public function testInterfacesCanUsesAsSubstitute()
{
$baseService = new BaseService();
$this->assertEquals(1, $baseService->process(new ChildImpl()));
}
/**
* @expectedException \TypeError
*/
public function testInterfacesCanUsesAsSubstitute_Exception()
{
$baseService = new BaseService();
$baseService->process(new SecondChildTypeImpl());
}
}
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为什么先测试通过?为什么php允许它?
PhpStorm警告你,你的代码可能允许的实例Base来BaseService::process是不是一个有效的Child实例,因此不能被传递给ChildService::process。
在您的第一个单元测试中,您提供了一个实例Child,它可以扩展Base,因此可以正常工作。
在第二个单元测试中,您实际上证明有可能导致PHP错误。PhpStorm只是在事先警告您,您的键入提示允许出现此问题。
如果BaseService::process将总是调用ChildService::process像你现在所拥有的,那么BaseService::process应该typehint它的参数是兼容ChildService::process也是如此。
我已经稍微修改了您的代码,重写了一些类名称以使其更简单,并删除了该getId方法。我只是想尽可能简单地显示它,以帮助您了解正在发生的事情。
interface Base {}
interface Child extends Base {}
interface Base2 extends Base {}
// This class implements Child, which extends Base. So this will meet either requirement.
class Class1 implements Child {}
// This class implements Base2, which extends Base.
// So this will meet any Base requirement, but NOT a Child requirement
class Class2 implements Base2 {}
class BaseService
{
/**
* Problem! We are requiring Base here, but then we pass the same argument to
* ChildService->process, which requires Child.
*
* 1) Class1 WILL work, since it implements Child which extends Base.
*
* 2) Class2 WILL NOT work. Or at least, we can't pass it to ChildService->process
* since it only implements Base2 which extends Base. It doesn't implement Child,
* therefore ChildService->process won't accept it.
*/
public function process(Base $base)
{
$childService = new ChildService($base);
return $childService->process($base);
}
}
class ChildService
{
/**
* I will ONLY receive an instance that implements Child.
* Class1 will work, but not Class2.
*/
public function process(Child $child)
{
return $child->getId();
}
}
$service = new BaseService();
// I can do this! I'm passing in Child1, which implements Child, which extends Base.
// So it fulfills the initial Base requirement, and the secondary Child requirement.
$service->process(new Child1());
// I can't do this. While BaseService will initially accept it, ChildService will refuse
// it because this doesn't implement the Child interface as required.
$service->process(new Child2());
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