通过python将带有'th''st''rd''nd'的日期字符串转换为日期格式

Question

我正在使用美丽的汤取消日期的网站.这是CSS

<div id="listing-details-list">
<h3 class="listing-details-header">
Details:
<span>Posted on: 14th June 2016</span>
</h3>
</div>

我用来获取日期的代码就是这个

# date
    try:
        date=soup.find("h3","listing-details-header") 
        date_result= str(date.get_text().encode("utf-8").strip()[20:])
        print "\nPublished date: ", date_result
    except StandardError as e:
        date_result="Error was {0}".format(e)
        print date_result

我得到的结果是一个字符串日期.一些样本是

23rd June 2016
21st July 2016
20th July 2016
3rd July 2016

现在,我希望日期是一个正确的日期,格式为'type',如下所示,以便我可以对它进行计算

23/6/2016
21/7/2016
20/7/2016
3/7/2016

在我的代码中,最好的方法是获得所需的日期？

我希望以这样的方式保存日期:

Month= 6
Day = 23
Year = 2016

---

我尝试了标记为最佳答案的解决方案并且有效

try:
        date=soup.find("h3","listing-details-header") 
        date_result= str(date.get_text().encode("utf-8").strip()[20:])
        date_result=parse(date_result) #added
        month = date_result.month
        day = date_result.day
        year = date_result.year
        print month
        print day
        print year

        print "\nPublished date: ", date_result
    except StandardError as e:
        date_result="Error was {0}".format(e)
        print date_result

Answer 1

要解析日期,我只需让dateutil解析器完成工作:

>>> from dateutil.parser import parse
>>> l = ["23rd June 2016", "21st July 2016", "20th July 2016", "3rd July 2016"]
>>> for item in l:
...     parse(item)
... 
datetime.datetime(2016, 6, 23, 0, 0)
datetime.datetime(2016, 7, 21, 0, 0)
datetime.datetime(2016, 7, 20, 0, 0)
datetime.datetime(2016, 7, 3, 0, 0)

您将获得datetime可用于执行与日期或时间相关的计算的实例.

我还会改进您在页面上找到所需元素的方式并提取日期:

from dateutil.parser import parse
from bs4 import BeautifulSoup

data = """
<div id="listing-details-list">
<h3 class="listing-details-header">
Details:
<span>Posted on: 14th June 2016</span>
</h3>
</div>"""

soup = BeautifulSoup(data, "html.parser")

for item in soup.find_all("span", text=lambda text: text and text.startswith("Posted on:")):
    date_string = item.get_text().split(": ")[-1]
    print(parse(date_string))