TypeError:&''float'和'numpy.float64'不支持的操作数类型

Pat*_*bug 8 python numpy typeerror

我正在尝试使用以下代码将连续变量转换为分类变量:

def score_to_categorical(x):
    if x<0.25:
        return 'very bad'
    if x>=0.25 & x<0.5:
        return 'bad'
    if x>=0.5 & x<0.75:
        return 'good'
    else:
        return 'very good'

ConceptTemp['Score'] = ConceptTemp['Score'].apply(score_to_categorical)
ConceptTemp1['Score'] = ConceptTemp1['Score'].apply(score_to_categorical)
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但是我收到以下错误:

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-72-7ec42b055d4f> in <module>()
----> 1 ConceptTemp['Score'] = ConceptTemp['Score'].apply(score_to_categorical)
      2 ConceptTemp1['Score'] = ConceptTemp1['Score'].apply(score_to_categorical)

E:\Anaconda2\lib\site-packages\pandas\core\series.pyc in apply(self, func, convert_dtype, args, **kwds)
   2167             values = lib.map_infer(values, lib.Timestamp)
   2168 
-> 2169         mapped = lib.map_infer(values, f, convert=convert_dtype)
   2170         if len(mapped) and isinstance(mapped[0], Series):
   2171             from pandas.core.frame import DataFrame

pandas\src\inference.pyx in pandas.lib.map_infer (pandas\lib.c:62578)()

<ipython-input-11-1c4f9c7bfafe> in score_to_categorical(x)
     10     if x<0.25:
     11         return 'very bad'
---> 12     if x>=0.25 & x<0.5:
     13         return 'bad'
     14     if x>=0.5 & x<0.75:

TypeError: unsupported operand type(s) for &: 'float' and 'numpy.float64'
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我会尽管如此float并且numpy.float64会兼容,但似乎并非如此.

在这方面的任何帮助将不胜感激.

TIA.

For*_*Bru 13

这里x>=0.25 & x<0.5 &执行按位与运算(例如,1 & 52是零,这将被视为False),而你一定意味着同时检查是否x>=0.25 x<0.5属实.

所以,这样做:

x>=0.25 and x<0.5
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同样的错误在下一行.