Aja*_*jay 10 c++ memory-leaks unique-ptr c++11 c++14
我没有得到以下声明会做什么(特别是第二行)?
auto buff = std::make_unique<int[]>(128);
buff = std::make_unique<int[]>(512);
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第二次调用make_unique后跟赋值运算符将取消分配第一次调用分配的内存,还是会出现内存泄漏?我必须要用buff.reset(new int[512]);吗?
我调试了它,但没有找到任何operator=被调用,也没有调用任何析构函数(by unique_ptr).
调用移动赋值运算符,这样做
if (this != &_Right)
{ // different, do the swap
reset(_Right.release());
this->get_deleter() = _STD move(_Right.get_deleter());
}
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这里没有泄漏,因为它会重置,这将解除分配.
gcc 5.3:
#include <memory>
extern void emit(int*);
int main()
{
// declare and initialise buf
auto buff = std::make_unique<int[]>(128);
// make_unique on the RHS returns a temporary
// - therefore an r-value reference
// therefore this becomes and operator=(unique_ptr&&)
// (move-assignment)
buff = std::make_unique<int[]>(512);
// something to get the compiler to emit code
emit(buff.get());
}
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产量装配:
main:
pushq %r12
movl $512, %edi
pushq %rbp
pushq %rbx
call operator new[](unsigned long) ; <-- new (1)
movl $64, %ecx
movq %rax, %rbp
xorl %eax, %eax
movq %rbp, %rdi
rep stosq
movl $2048, %edi
call operator new[](unsigned long) ; <<-- new (2)
movl $2048, %edx
xorl %esi, %esi
movq %rax, %rdi
movq %rax, %rbx
call memset
movq %rbp, %rdi
call operator delete[](void*) ;<-- delete (1)
movq %rbx, %rdi
call emit(int*)
movq %rbx, %rdi
call operator delete[](void*) ;<-- delete (2)
popq %rbx
xorl %eax, %eax
popq %rbp
popq %r12
ret
movq %rax, %r12
movq %rbp, %rbx
.L3:
movq %rbx, %rdi
vzeroupper
call operator delete[](void*) ;<-- handles a failed assignment
movq %r12, %rdi
call _Unwind_Resume
movq %rax, %r12
jmp .L3
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