SqlAlchemy关系和棉花糖

Zee*_*e18 3 json sqlalchemy flask marshmallow

我试图返回JSON甚至返回的一对多sqlalchemy查询的完整字符串。我现在正在使用棉花糖尝试执行此操作,但它会不断返回不完整的数据

我有两个模型定义为:

class UserModel(db.Model):
    __tablename__ = 'usermodel'
    id = db.Column(db.Integer, primary_key=True)
    username = db.Column(db.String(80), unique=True)
    password = db.Column(db.String(120))
    weekday = db.relationship('weekDay', cascade='all,delete-orphan', single_parent=True, backref=db.backref('usermodel', lazy='joined'))

class weekDay(db.Model):
    __tablename__ = 'weekday'
    id = db.Column(db.Integer, primary_key=True)
    #Defining the Foreign Key on the Child Table
    dayname = db.Column(db.String(15))
    usermodel_id = db.Column(db.Integer, db.ForeignKey('usermodel.id'))
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我定义了两个模式

class WeekdaySchema(Schema):
    id = fields.Int(dump_only=True)
    dayname = fields.Str()

class UserSchema(Schema):
    id = fields.Int(dump_only=True)
    username = fields.Str()
    password = fields.Str()
    weekday = fields.Nested(WeekdaySchema)
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最后我运行命令(在userName变量中传递名称)

 userlist = UserModel.query.filter_by(parentuser=userName).all()
 full_schema = UserSchema(many=True)
 result, errors = full_schema.dump(userlist)
 print (result)
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在尝试对其进行Jsonify之前,我先打印结果以查看:我的工作日对象完全为空

'weekday': {}
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没有人知道我如何正确地做到这一点

Fil*_*ral 7

这是一对多关系,您必须在上UserSchema指出

class UserSchema(Schema):
    id = fields.Int(dump_only=True)
    username = fields.Str()
    password = fields.Str()
    weekday = fields.Nested(WeekdaySchema, many=True)
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