如何将这两个JTokens合并为一个JToken.这听起来应该很简单,但无法绕过它.
{
"data":[
{
"ID":"53a1862000404a304942546b35519ba3",
"name":"Private Approval Process: Draft Document CPL",
"objCode":"ARVPTH"
}]
}
{
"data":[
{
"ID":"53a1838200401324eb1ec66562e9d77d",
"name":"Private Approval Process: Draft Document CPL",
"objCode":"ARVPTH"
}]
}
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谢谢您的帮助!
这是我到目前为止所尝试的:
我开始将第一个对象分配给变量Jtoken pageOne然后,我尝试将其连接到第二个变量JToken allPages.我有一个循环,带回多个页面,每个页面有三个字段.最终目标是获取每个页面并创建一个Token包含其中所有页面的大J.
这样的事情:
for (int page = 0; page <= recCount; page += 2000)
{
//Get data
pageOne = getJsonData();
allPages.Concat(pageOne);
}
return allPages;
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您可以使用JContainer.Merge(Object, JsonMergeSettings)将一个合并JObject到另一个.请注意,可以JsonMergeSettings.MergeArrayHandling控制数组的合并方式.在MergeArrayHandlingEnumeration文档中,可能的合并选项包括:
Run Code Online (Sandbox Code Playgroud)Concat 0 Concatenate arrays. Union 1 Union arrays, skipping items that already exist. Replace 2 Replace all array items. Merge 3 Merge array items together, matched by index.
因此合并使用MergeArrayHandling.Concat如下,其中allPages和pageOne都是类型JContainer(或子类,如JObject):
JContainer allPages = null;
var settings = new JsonMergeSettings { MergeArrayHandling = MergeArrayHandling.Concat };
for (int page = 0; page <= recCount; page += 2000)
{
//Get data
var pageOne = (JContainer)getJsonData(page);
if (allPages == null)
allPages = pageOne;
else
allPages.Merge(pageOne, settings);
}
return allPages;
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得到:
{
"data": [
{
"ID": "53a1862000404a304942546b35519ba3",
"name": "Private Approval Process: Draft Document CPL",
"objCode": "ARVPTH"
},
{
"ID": "53a1838200401324eb1ec66562e9d77d",
"name": "Private Approval Process: Draft Document CPL",
"objCode": "ARVPTH"
}
]
}
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合并使用时Replace给出:
{
"data": [
{
"ID": "53a1838200401324eb1ec66562e9d77d",
"name": "Private Approval Process: Draft Document CPL",
"objCode": "ARVPTH"
}
]
}
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如果您的变量属于类型JToken,则需要将它们转换为JContainer.(不是容器的JSON原语不能合并.)
JsonMergeSettings.MergeNullValueHandlingnull根据需要控制是否合并或忽略值.