引起:com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException:无法识别的字段"Status"

Question

我收到以下错误消息,我有Status类但它没有被识别.我不知道如何继续,也无法在线找到答案.

错误

   org.springframework.http.converter.HttpMessageNotReadableException: Could 
   not read JSON: Unrecognized field "Status" (class 
   com.myproject.ticket.EventsResponse), not marked as ignorable (3 known 
   properties: "events", "status", "page"])
      ....
   Caused by: 
   com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: 
   Unrecognized field "Status" (class com.myproject.ticket.EventsResponse), 
   not marked as ignorable (3 known properties: "events", "status", "page"])

EventsResponse

@XmlRootElement(name = "EventsResponse")
@XmlAccessorType(XmlAccessType.FIELD)
public class EventsResponse {
    @XmlElement(name = "Status")
    private Status status;
    @XmlElement(name = "Paging")
    private Page page;
    @XmlElementWrapper(name="Events")
    @XmlElement(name = "Event")
    private List<Event> events;

    .....

状态

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Status {
    @XmlElement(name = "Version")
    private double version;
    @XmlElement(name = "TimeStampUtc")
    private Date timeStampUtc;
    @XmlElement(name = "Code")
    private int code;
    @XmlElement(name = "Message")
    private String message;
    @XmlElement(name = "Details")
    private String details;

响应

<EventsResponse xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
    <Status>
        <Version>2.0</Version>
        <TimeStampUtc>2016-06-11T09:32:21</TimeStampUtc>
        <Code>0</Code>
        <Message>Success</Message>
        <Details />
    </Status>
    <Paging>
        <PageNumber>1</PageNumber>
        <PageSize>50</PageSize>
        <PageResultCount>15</PageResultCount>
        <TotalResultCount>15</TotalResultCount>
        <TotalPageCount>1</TotalPageCount>
    </Paging>
    <Events>
        <Event>

我添加了以下状态,但我仍然收到相同的错误.

@XmlElement(name = "Status")
@JacksonXmlProperty(localName = "Status")
private Status status;

Answer 1

假设您使用 Jackson 来反序列化 XML 对象，您有两个选择。最简单的方法是使用 Jackson 自己的 XML 注释来代替 JAXB 注释，或者与 JAXB@XmlElement注释一起使用。例如：

@XmlElement(name = "Status")
@JacksonXmlProperty(localName = "Status")
private Status status;

（@XmlElement注释位于jackson-dataformat-xmlMaven 中的包中 - 该版本应与您的其他 Jackson 包版本相匹配。）

另一种方法是注册 AnnotationIntrospector 作为反序列化链的一部分 - 即。（来自单元测试）：

    XmlMapper mapper = new XmlMapper();
    AnnotationIntrospector aiJaxb = new JaxbAnnotationIntrospector(TypeFactory.defaultInstance());
    mapper.setAnnotationIntrospector(aiJaxb);
    // EVENTS_RESPONSE is the incoming XML
    EventsResponse response = mapper.readValue(EVENTS_RESPONSE, EventsResponse.class);

这会识别@XmlElement注释。例如，如果您需要将其作为 Spring 配置的一部分包含在内，则此答案中有更多详细信息。

（为了使用该类JaxbAnnotationIntrospector，您需要jackson-module-jaxb-annotationMaven 中的模块。）