SPARQL查询DBLP

Question

我正在运行此查询

SELECT *
WHERE
{
?s dc:creator ?name .
?s rdf:type swrc:Article .
FILTER regex(str(?name), "Jeffrey", "D.", "Ullman") .
}

我收到的错误是:

Encountered " "," ", "" at line 16, column 41.
Was expecting one of:
    <LANGTAG> ...
    <INTEGER_POSITIVE> ...
    <DECIMAL_POSITIVE> ...

有什么问题,我不符合准则吗？我搜索了一下,我在各种帖子中找到了相同的语法.

编辑:

当我要求的时候

SELECT * WHERE { ?s rdf:type swrc:Article . ?s dc:creator ?name . }

我回来了: s name <http://dblp.l3s.de/d2r/resource/publications/conf/www/BeszteriV07> [http] <http://dblp.l3s.de/d2r/resource/authors/Istvan_Beszteri> [http]在一行中,第一个URI是?s第二个,第二个是?name.

现在我知道有一个名为"Jeffrey D. Ullman"的作者,我查询:

SELECT * WHERE { ?s rdf:type swrc:Article . ?s dc:creator ?name . FILTER regex(str(?name), "Jeffrey") } LIMIT 10.

然后我回过头来举个例子: s name <http://dblp.l3s.de/d2r/resource/publications/conf/www/LimWPVA07> [http] <http://dblp.l3s.de/d2r/resource/authors/Jeffrey_Scott_Vitter> [http]

所以这里的问题是我如何能够匹配"Jeffrey D. Ullman"并查看他撰写的所有文章.

Answer 1

您的正则表达式函数语法不正确请参阅SPARQL1.1规范.请注意,正则表达式正好采用两个或三个参数,第一个是文本,第二个是模式,最后一个是包含标志的可选字符串.

17.4.3.14 REGEX

xsd:boolean  REGEX (string literal text, simple literal pattern) 
xsd:boolean  REGEX (string literal text, simple literal pattern, simple literal flags)