vik*_*mar 0 java multithreading java-threads
为什么在同一类锁上等待并通知函数不能正常工作?
请参阅以下检查代码,了解等待和通知功能及其输出.
输出:
Thread-1
Thread-2
Thread-2 after notify
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预期结果:
Thread-1
Thread-2
Thread-2 after notify
Thread-1 after wait
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码:
public class WaitAndNotify1 {
public static void main(String[] args) {
Thread t1=new Thread(new Runnable(){
@Override
public void run(){
System.out.println("Thread-1");
try {
synchronized (this) {
wait();
System.out.println("Thread-1 after wait");
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
});
Thread t2=new Thread(new Runnable(){
@Override
public void run(){
try {
Thread.sleep(4000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Thread-2");
synchronized (this) {
notify();
System.out.println("Thread-2 after notify");
}
}
});
t1.start();
t2.start();
}
}
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您使用this的是匿名内部类 - 因此它引用了该匿名内部类的实例.有两个不同的实例(不同的匿名内部类),因此您正在调用wait()与您正在调用的对象不同的对象notify().
您实际上没有WaitAndNotify1要同步的实例.您可以将代码移动到实例方法,然后用于WaitAndNotify1.this引用实例 - 此时您将获得预期的输出:
public class WaitAndNotify1 {
public static void main(String[] args) {
new WaitAndNotify1().test();
}
public void test() {
Thread t1=new Thread(new Runnable(){
@Override
public void run(){
System.out.println("Thread-1");
try {
synchronized (WaitAndNotify1.this) {
WaitAndNotify1.this.wait();
System.out.println("Thread-1 after wait");
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
});
Thread t2=new Thread(new Runnable(){
@Override
public void run(){
try {
Thread.sleep(4000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Thread-2");
synchronized (WaitAndNotify1.this) {
WaitAndNotify1.this.notify();
System.out.println("Thread-2 after notify");
}
}
});
t1.start();
t2.start();
}
}
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