ans:= RichEdit1.Text
for i:=1 to Length(ans) do
begin
RichEdit1.SelStart := i-1;
RichEdit1.SelLength:= 1;
if ans[i] = correct[i] then
RichEdit1.SelAttributes.Color := clRed
else
RichEdit1.SelAttributes.Color := clBlue;
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如果字母ans匹配字母与字母相同位置的字母correct,则为红色,否则为蓝色.
我的问题是,当我再次输入时,整个RichEdit1文本的颜色与第一个字母相同(如果第一个字母RichEdit1是蓝色,则整个文本变为蓝色).
顺便说一句,这不是我简化它的实际代码,因为有多个TRichEdits.
TRichEdits是只读的,我通过类似的方式分配字母RichEdit1.Text := RichEdit1.Text+Key;
(这样做是因为它是一个多键盘程序,我需要分开用户输入)
这是正确的行为吗?如何阻止我的颜色更改覆盖默认颜色?
更新:解决它...以一种草率的方式(每当有人打字时应用默认颜色),但我保持这个开放,以防有人提出更好的解决方案.
正如您已经发现的那样,完成后必须重置默认颜色,例如:
ans := RichEdit1.Text;
for i := 1 to Length(ans) do
begin
RichEdit1.SelStart := i-1;
RichEdit1.SelLength := 1;
if ans[i] = correct[i] then
RichEdit1.SelAttributes.Color := clRed
else
RichEdit1.SelAttributes.Color := clBlue;
end;
RichEdit1.SelStart := RichEdit1.GetTextLen;
RichEdit1.SelLength := 0;
RichEdit1.SelAttributes.Color := RichEdit1.Font.Color;
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有一种更有效的方法来处理这个问题,而不是一次着色一个字母,例如:
const
colors: array[Boolean] of TColor = (clRed, clBlue);
var
ans: string;
start, len: Integer;
cur_state: Boolean;
procedure ColorRange(AStart, ALength: Integer; AColor: TColor);
begin
RichEdit1.SelStart := AStart;
RichEdit1.SelLength := ALength;
RichEdit1.SelAttributes.Color := AColor;
end;
begin
RichEdit1.Lines.BeginUpdate;
try
ans := RichEdit1.Text;
start := 0;
len := 0;
cur_start := False;
for i := 1 to Length(ans) do
begin
if (ans[i] = correct[i]) = cur_state then
Inc(len)
else begin
if len > 0 then
ColorRange(start, len, colors[cur_state]);
start := i-1;
len := 1;
cur_state := not cur_state;
end;
end;
if len > 0 then
ColorRange(start, len, colors[cur_state]);
ColorRange(RichEdit1.GetTextLen, 0, RichEdit1.Font.Color);
finally
RichEdit1.Lines.EndUpdate;
end;
end;
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此外,使用Text属性追加单个Char效率非常低.请改用SelText属性,例如:
RichEdit1.SelStart := RichEdit1.GetTextLen;
RichEdit1.SelLength := 0;
RichEdit1.SelAttributes.Color := ...; // optional
RichEdit1.SelText := Key;
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