Ers*_*man 10 android android-canvas android-vectordrawable
您好我的自定义视图:
MyCustomView extends View
我做了一个VectorDrawable
mMyVectorDrawable = VectorDrawableCompat.create(getContext().getResources(), R.drawable.ic_some_image, null);
我已经设定了界限
mMyVectorDrawable.setBounds(0, 0, mMyVectorDrawable.getIntrinsicWidth(), mMyVectorDrawable.getIntrinsicHeight());
我在画布上绘制它
mMyVectorDrawable.draw(canvas);
我在0,0位置看到了图像
但我该如何定位呢？如何定位Rect,我认为前两个参数setBounds将是X和Y坐标的开始绘图,但这只会影响尺寸.
如何将矢量绘图放在画布上？
谢谢阅读
Dan*_*gen 12
您可以在将drawable绘制到其上之前翻译画布.
mMyVectorDrawable.setBounds(0, 0, width, height);
canvas.translate(dx, dy);
mMyVectorDrawable.draw(canvas);
值dx并dy指定(0, 0)将绘制下一个drawable 的坐标的偏移量.
如果需要,您也可以在以后撤消翻译:
canvas.translate(-dx, -dy);
这个问题有点老了，但如果它可以帮助某人，我有一个基于这个的答案。
这个想法是使用以下方法获取矢量可绘制：
Drawable drawable = AppCompatDrawableManager.get().getDrawable(context, R.drawable.my_drawable);
然后我们直接从这个 Drawable 中获取 Bitmap 大小我们想要保持质量。然后，因为我们有一个位图，所以我们可以把它画在我们想要的地方。
注意：在你的 build.gradle的defaultConfig部分，不要忘记把这一行放在retro-compatibility：
vectorDrawables.useSupportLibrary = true
这是从 Drawable 中获取位图的代码：
/**
* Extract the Bitmap from a Drawable and resize it to the expectedSize conserving the ratio.
*
* @param drawable Drawable used to extract the Bitmap. Can be null.
* @param expectSize Expected size for the Bitmap. Use {@link #DEFAULT_DRAWABLE_SIZE} to
* keep the original {@link Drawable} size.
* @return The Bitmap associated to the Drawable or null if the drawable was null.
* @see <html><a href="/sf/answers/742051551/">Stackoverflow answer</a></html>
*/
public static Bitmap getBitmapFromDrawable(@Nullable Drawable drawable, int expectSize) {
Bitmap bitmap;
if (drawable == null) {
return null;
}
if (drawable instanceof BitmapDrawable) {
BitmapDrawable bitmapDrawable = (BitmapDrawable) drawable;
if (bitmapDrawable.getBitmap() != null) {
return bitmapDrawable.getBitmap();
}
}
if (drawable.getIntrinsicWidth() <= 0 || drawable.getIntrinsicHeight() <= 0) {
bitmap = Bitmap.createBitmap(1, 1, Bitmap.Config.ARGB_8888); // Single color bitmap will be created of 1x1 pixel
} else {
float ratio = (expectSize != DEFAULT_DRAWABLE_SIZE)
? calculateRatio(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), expectSize)
: 1f;
int width = (int) (drawable.getIntrinsicWidth() * ratio);
int height = (int) (drawable.getIntrinsicHeight() * ratio);
bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
}
Canvas canvas = new Canvas(bitmap);
drawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
drawable.draw(canvas);
return bitmap;
}
/**
* Calculate the ratio to multiply the Bitmap size with, for it to be the maximum size of
* "expected".
*
* @param height Original Bitmap height
* @param width Original Bitmap width
* @param expected Expected maximum size.
* @return If height and with equals 0, 1 is return. Otherwise the ratio is returned.
* The ration is base on the greatest side so the image will always be the maximum size.
*/
public static float calculateRatio(int height, int width, int expected) {
if (height == 0 && width == 0) {
return 1f;
}
return (height > width)
? expected / (float) width
: expected / (float) height;
}
小智 5
正如@pskink 所说，这工作正常：
setBounds(x, y, intrinsic_width + x, intrinsic_height + y)
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