Wil*_*ver 6 java xssf nosuchfieldexception
我遵循了使用Apache POI XSSF构建工作簿的简单指南.按照相同的指南,我能够写一个Excel工作表,但是当试图从一个读取时,我收到代码后显示的错误.
码:
try {
FileInputStream file = new FileInputStream(new File("howtodoinjava_demo.xlsx"));
// Create Workbook instance holding reference to .xlsx file
XSSFWorkbook workbook = new XSSFWorkbook(file);
// Get first/desired sheet from the workbook
XSSFSheet sheet = workbook.getSheetAt(0);
// Iterate through each rows one by one
Iterator<Row> rowIterator = sheet.iterator();
while (rowIterator.hasNext()) {
Row row = rowIterator.next();
// For each row, iterate through all the columns
Iterator<Cell> cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
Cell cell = cellIterator.next();
// Check the cell type and format accordingly
switch (cell.getCellType()) {
case Cell.CELL_TYPE_NUMERIC:
System.out.print(cell.getNumericCellValue() + "t");
break;
case Cell.CELL_TYPE_STRING:
System.out.print(cell.getStringCellValue() + "t");
break;
}
}
System.out.println("");
}
file.close();
} catch (Exception e) {
e.printStackTrace();
}
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错误输出:
org.apache.poi.openxml4j.opc.internal.ZipHelper中org.apache.poi.openxml4j.opc.internal.ZipHelper.verifyZipHeader(ZipHelper.java:179)中的线程"main"java.lang.NoSuchFieldError:RAW_XML_FILE_HEADER中的异常.openZipStream(ZipHelper.java:228)org.apache.poi.openxml4j.opc.ZipPackage.(ZipPackage.java:93)org.apache.poi.openxml4j.opc.OPCPackage.open(OPCPackage.java:294)在org.apache.poi.util.PackageHelper.open(PackageHelper.java:37)at org.apache.poi.xssf.usermodel.XSSFWorkbook.(XSSFWorkbook.java:273)at com.wtolliver.spring.test.ReadExcel. readExcel(ReadExcel.java:18)at com.wtolliver.spring.test.App.main(App.java:17)
环顾四周后.我浏览了APACHE POI的文档,发现这是常量之一(不是我知道这意味着什么).但最终,我意识到我使用的所有教程都是2014年之前的,所以我只是将我的Maven POM更改为apache POI 3.11和POI-OOXML.它现在正在工作.
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