Kam*_* G. 0 php model-view-controller laravel
我是Laravel的新手,无法将数据发布到控制器。我找不到相应的文档。我想要在Laravel中做与C#MVC类似的事情。
<form action="/someurl" method="post">
<input type="text" name="someName" />
<input type="submit">
</form>
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控制者
[HttpPost]
public ActionResult SomeUrl(string someName)
{
...
}
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您应该使用路线。
你的 .html
<form action="{{url('someurl')}}" method="post">
<input type="text" name="someName" />
<input type="submit">
</form>
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在 routes.php
Route::post('someurl', 'YourController@someMethod');
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终于在 YourController.php
public function someMethod(Request $request)
{
dd($request->all()); //to check all the datas dumped from the form
//if your want to get single element,someName in this case
$someName = $request->someName;
}
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小智 5
这效果最好
<form action="{{url('someurl')}}" method="post">
@csrf
<input type="text" name="someName" />
<input type="submit">
</form>
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在 web.php
Route::post('someurl', 'YourController@someMethod');
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并在您的控制器中
public function someMethod(Request $request)
{
dd($request->all()); //to check all the datas dumped from the form
//if your want to get single element,someName in this case
$someName = $request->someName;
}
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