我在codeigniter中遇到uri段的麻烦我正在寻找开发产品和产品细节,所以我为它创建了一个控制器并传递了产品名称的参数以在url中显示产品名称,所以我的url将变成这样的
本地主机/ PROJECT_NAME /产品/ PRODUCT_NAME
这部分对我来说工作正常,但我很困惑如果我想显示为产品类别和产品名称,我试图让我的网址像这样
localhost/project_name/products/category_name/product_name
所以当我传入类别名称时,我将如何执行此操作,它显示我找不到404找不到您请求的页面.有时会显示直接产品,有时候如果用户通过类别浏览产品详细信息,那么类别名称将在网址中传递,以及这些部分的工作方式如何?我对此很困惑
这是我的产品控制器
public function products($product_name) {
if($this->uri->segment(3)) {
$category = ucwords(str_replace('-', " ", $product_name));
$product = ucwords(str_replace('-', " ", $this->uri->segment(3)));
} else {
$product = ucwords(str_replace('-', " ", $product_name));
}
$page_data = $this->get_data->get_Data($product, 'name', 'products');
$data['title'] = 'Products - ' . $page_data->row()->name;
$data['body_class'] = 'poductsdetails';
$this->load->view('includes/header.php', $data);
$this->load->view('templates/navigation.php');
$data['content'] = array(
'name' => $page_data->row()->name,
'price' => $page_data->row()->price,
'description' => $page_data->row()->description,
'picture' => $page_data->row()->picture,
'category' => $page_data->row()->category,
);
$this->load->view('products/details', $data);
$this->load->view('templates/footer-form.php');
$this->load->view('includes/footer.php');
}
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这是我创建的路线
$route['default_controller'] = 'home';
$route['admin'] = 'admin/index';
$route['admin/([a-z])'] = 'admin/$1';
$route['products/(:any)'] = 'home/products/$1';
$route['products/(:any)'] = 'home/products/$1/$2';
$route['products/(:any)'] = 'home/products/$1/$2/$3';
$route['(:any)'] = 'home/page/$1';
$route['(:any)'] = 'home/page/$1/$2';
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你刚刚在路线中传递了一个参数,这就是它无法找到的原因
像这样改变你的路线
$route['products/(:any)'] = 'home/products/$1';
$route['products/(:any)/(:any)'] = 'home/products/$1/$2';
$route['products/(:any)/(:any)/(:any)'] = 'home/products/$1/$2/$3';
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它会工作.