抱歉,如果这个问题重复,我却没有找到一个明显的答案.我是一个完整的新手与PHP,善良!当我加载以下代码时,if(isset($_POST['test']))即使我没有按下按钮,它似乎也会运行"test".我只想按下" test"按钮时执行代码.我该如何解决这个问题？
<?php
if(isset($_POST['update'])) {
$content=simplexml_load_file("books.xml");
$value=$content->book->price;
$sum=$content->book->price;
}
if(isset($_POST['test'])) {
$content=simplexml_load_file("books.xml");
$value=$content->book->price;
$content->book->price = $value + 1.0;
$content->asXML("books.xml");
$sum=$content->book->price;
}
?>
<body>
<form method="post">
<input type="checkbox" id="i1check1" onchange="toggleDisabled(this.checked)"> Alarm 01
<input type="text" id="i1text1" name="i1" size="80" maxlength="128" value="<?php echo @$sum;?>"/>
<input type="submit" id="i1btn1" name="update" value="Update"/>
<input type="submit" id="i1btn2" name="test" value="Test"/>
</form>
<script>
function toggleDisabled(_checked) {
document.getElementById('i1text1').disabled = _checked ? false : true;
document.getElementById('i1btn1').disabled = _checked ? false : true;
}
</script>
</body>
请尝试一下
if(isset($_POST['update']) && $_POST['update'] == "Update"){
$content=simplexml_load_file("books.xml");
$value=$content->book->price;
$sum=$content->book->price;
}
if(isset($_POST['test']) && $_POST['test'] == "Test"){
$content=simplexml_load_file("books.xml");
$value=$content->book->price;
$content->book->price = $value + 1.0;
$content->asXML("books.xml");
$sum=$content->book->price;
}