在SQL Server中遇到一个查询

Question

我有一张名为的桌子calci.以下是样本数据

CREATE TABLE calci
    (RN int, FREQ int, price int)
;

INSERT INTO calci
    (RN, FREQ, price)
VALUES
    (1, 1, 3),
    (2, 2, 4),
    (3, 3, 5),
    (4, 4, 6),
    (5, 5, 7),
    (6, 6, 8),
    (7, 1, 5),
    (8, 2, 6),
    (9, 3, 9),
    (10, 4, 7),
    (11, 5, 5),
    (12, 6, 1),
    (13, 1, 3)
;

根据freq(1-6)的总和我只需要3条记录

结果应该是这样的

price
33 -----sum of first 6 records    
33 -----sum of next six records    
3  -----sum of last six record i.e last record

Answer 1

请检查以下查询，这将解决上述问题

select sum(price) from calci  group by (rn- freq)